I have a file that I have to read some numbers from and put them into an array. The only problem is that I don't know how to find the size of it. I am given the maximum size of the array but the numbers don't fill the array completely. I tried many different ways to make it work but it doesn't read the correct values from the file. Is there any other way to do it without sizeof?
我有一个文件,我必须从中读取一些数字并将它们放入一个数组中。唯一的问题是我不知道如何找到它的大小。我被赋予了数组的最大大小,但数字并没有完全填满数组。我尝试了许多不同的方法使其工作,但它没有从文件中读取正确的值。有没有其他方法可以做到没有sizeof?
#include<stdio.h>
#define MAX_NUMBER 25
int main(void)
{
int test[];
int size;
FILE* sp_input;
int i;
sp_input = fopen("a20.dat", "r");
if (sp_input == NULL)
printf("\nUnable to open the file a20.dat\n");
else
{
while( fscanf(sp_input, "%d", &test[i])!=EOF)
{
size=sizeof(test)/sizeof(test[0]);
}
for(i = 0; i < size; i++)
printf("\na[%d]=%d has a size of %d\n", i,test[i],size);
fclose(sp_input);
}
return 0;
}
2 个解决方案
#1
2
If you increment i
each time you successfully do a fscanf
, it will serve as a count of the number of items read.
如果每次成功执行fscanf时增加i,它将作为读取项目数的计数。
i = 0;
while (fscanf(sp_input, "%d", &test[i]) == 1) {
i = i + 1;
}
// Now, i is the number of items in the list, and test[0] .. test[i-1]
// are the items.
Edit: As @chux pointed out, in this case it's better to compare to 1, the expected number of items scanned, on each call. If a bogus input is provided (non-digits), there's still a problem and you should stop.
编辑:正如@chux指出的那样,在这种情况下,最好在每次调用时与1(预期扫描的项目数)进行比较。如果提供虚假输入(非数字),仍然存在问题,您应该停止。
#2
1
Define a maximum size array and continue looping as able.
定义最大大小数组并继续循环。
File input need not fill the array, just populate it as it can. Keep track, i
, of how many of test[]
was used and be sure not to overfill the array.
文件输入不需要填充数组,只需填充它即可。跟踪i,使用了多少个test [],并确保不要过度填充阵列。
#define MAX_NUMBER 25
int test[MAX_NUMBER];
FILE* sp_input = fopen("a20.dat", "r");
...
// Use `size_t` for array indexing
size_t i;
// do not read too many `int`
for (i=0; i<MAX_NUMBER; i++) {
if (fscanf(sp_input, "%d", &test[i]) != 1) {
break;
}
printf("test[%zu]=%d\n", i, test[i]);
}
#1
2
If you increment i
each time you successfully do a fscanf
, it will serve as a count of the number of items read.
如果每次成功执行fscanf时增加i,它将作为读取项目数的计数。
i = 0;
while (fscanf(sp_input, "%d", &test[i]) == 1) {
i = i + 1;
}
// Now, i is the number of items in the list, and test[0] .. test[i-1]
// are the items.
Edit: As @chux pointed out, in this case it's better to compare to 1, the expected number of items scanned, on each call. If a bogus input is provided (non-digits), there's still a problem and you should stop.
编辑:正如@chux指出的那样,在这种情况下,最好在每次调用时与1(预期扫描的项目数)进行比较。如果提供虚假输入(非数字),仍然存在问题,您应该停止。
#2
1
Define a maximum size array and continue looping as able.
定义最大大小数组并继续循环。
File input need not fill the array, just populate it as it can. Keep track, i
, of how many of test[]
was used and be sure not to overfill the array.
文件输入不需要填充数组,只需填充它即可。跟踪i,使用了多少个test [],并确保不要过度填充阵列。
#define MAX_NUMBER 25
int test[MAX_NUMBER];
FILE* sp_input = fopen("a20.dat", "r");
...
// Use `size_t` for array indexing
size_t i;
// do not read too many `int`
for (i=0; i<MAX_NUMBER; i++) {
if (fscanf(sp_input, "%d", &test[i]) != 1) {
break;
}
printf("test[%zu]=%d\n", i, test[i]);
}