我想删除所有空格

I have a string that is something like the example below,

我有一个字符串，类似于下面的例子，

assd *AA*the fox saw the outcome     *EAA*saassdsd

I want to remove the whitespace between AA and EAA using regex. Using the code below I can highlight everything between AA and EAA but I only want all the spaces to be highlighted. I believe this (.*) is grouping all the characters. Can someone point me in the right direction thanks?

我想使用正则表达式删除AA和EAA之间的空格。使用下面的代码我可以突出显示AA和EAA之间的所有内容，但我只希望突出显示所有空格。我相信这个（。*）正在对所有角色进行分组。有人能指出我正确的方向谢谢吗？

 \*AA\*(.*)\*EAA\*

1 个解决方案

#1

From your question, it appears that you want to remove all spaces from given string.

从您的问题，您似乎要删除给定字符串中的所有空格。

function sanitize($string)
{
    $re = "/^(.*?AA)(.*)(EAA.*)$/i";

    preg_match_all($re, $string, $matches);

    if($matches) {
        $p1 = $matches[1][0];
        $p2 = $matches[2][0];
        $p3 = $matches[3][0];

        $p2 = preg_replace("/\\s+/", "", $p2);

        $result = $p1.$p2.$p3;
        return $result;
    }
    return $string;
}

$str = "assd *AA*the fox saw the outcome     *EAA*saassdsd ";
print(sanitize($str))

This will render:

这将呈现：

assd *AA*thefoxsawtheoutcome*EAA*saassdsd

#1