如何形成Java Regex来拆分字符串？

I am looking for a Java Regex, so that I can break the following expresion : first using '-', but if '-' is used in a quotation mark it shoul be ignored.

我正在寻找一个Java Regex,以便我可以打破以下表达式:首先使用' - ',但如果在引号中使用' - '则应该忽略它。

e.g: a test - which "contains "-"" inside - a quotation mark. result should be an arry like this:

例如:一个测试 - “包含” - “”里面 - 一个引号。结果应该是这样的arry:

[0]: a test 
[1]: which "contains "-""  inside
[2]: a quotation mark

I am not really good with regular expression and will be thank full if anyone can help me :) thanks in advance

我对正则表达式并不是很好,如果有人可以帮助我,我会非常感谢:)提前感谢

2 个解决方案

#1

Check out Regex Planet to test out any regex's you make

查看Regex Planet以测试你所做的任何正则表达式

You should be able to achieve this with

你应该能够实现这一目标

String[] splitAray = yourString.Split("[^\"]-[^\"]")

Update using look ahead/behind so that the characters before and after - are not consumed

使用向前/向后更新以便不消耗前后的字符

String[] splitAray = yourString.Split("(?!\")-(?!\")")

#2

Solution using lookbehind and lookahead:

使用lookbehind和lookahead的解决方案:

String input = "a test - which \"contains \"-\" inside - a quotation mark";
String[] chunks = input.split("(?<!\")-(?!\")");
System.out.println(Arrays.toString(chunks));

OUTPUT:

[a test ,  which "contains "-" inside ,  a quotation mark]

EDIT: changing the first part of regexp ((?!\")) to (?<!\")

编辑:将正则表达式的第一部分((?!\“))更改为(?

#1