Java regex拆分字符串不起作用。

I need to split a string with regex in Java.

我需要用Java与regex分割一个字符串。

I need to get an array : A, B, 01/01/2016 12:31, D

我需要得到一个数组:A, B, 01/2016 12:31, D

why my regex doesn't work ? it will output the original string.

为什么我的regex不起作用?它将输出原始字符串。

String source = "A|B|[01/01/2016 12:31]|D";     
String regex = "\\|\\|\\[.*\\]\\|";

String[] array = source.split(regex);
for(String data: array){
    System.out.println(data);
}

2 个解决方案

#1

The regex does not match the input string as it expects two consecutive pipes (at the start of the pattern). To be more precise, \|\|\[.*\]\| matches 2 pipes followed by a [ followed with zero or more characters other than a newline (as many as possible) followed with ] and a |.

regex不匹配输入字符串，因为它期望两个连续的管道(在模式的开始)。更准确地说，|\|\[。\|匹配两个管道，后跟一个[后跟除换行符(尽可能多)以外的零或多个字符]和一个|。

You need to use the following regex:

您需要使用以下regex:

String regex = "[|\\[\\]]+";

See IDEONE demo

看到IDEONE演示

This regex will match one or more characters: |, ] or [.

这个regex将匹配一个或多个字符:|，]或[。

#2

Modifying the 2nd line to something as below for the input string format and calling split with -1 should handle all situations when the tokens are empty including the last one

将第2行修改为如下所示的输入字符串格式，并调用split with -1，应该可以处理所有令牌为空的情况，包括最后一个令牌

String regex = "((\\|\\[)|(\\]\\|)|(\\|))";

String[] array = source.split(regex, -1);

the above gives following output for 'A|B|[01/01/2016 12:31]|D' in case of empty D as well it prints a zero string.

上面给出了“A|B|[01/ 2016 12:31]|D”的输出，如果D为空，它也会打印一个零字符串。

A
B
01/01/2016 12:31
D

This though will work for input strings of the format A|B|[C]|D, the other regex mentioned on the thread [[|\[\]]]+ will handle square brackets showing anywhere in the input along with | separator as long as there are no zero strings, for example A||[C]|D will result in shifting of tokens.

这将适用于格式A|B|[C]|D的输入字符串，线程上提到的另一个regex[[[[|\[\]]]]+将处理显示输入任何地方的方括号以及|分隔符，只要没有任何字符串，例如||[C]|D将导致令牌移位。

#1