确定字符串是否是正则表达式的全部大写字母

How can you determine if a string is all caps with a regular expression. It can include punctuation and numbers, just no lower case letters.

如何确定字符串是否都是带正则表达式的大写字母。它可以包括标点符号和数字，只是没有小写字母。

8 个解决方案

#1

m/^[^a-z]*$/

For non-English characters,

对于非英文字符，

m/^[^\p{Ll}]*$/

#2

That sounds like you want: ^[^a-z]*$

这听起来像你想要的：^ [^ a-z] * $

#3

Why not just use if(string.toUpperCase() == string)? ._. Its more "elegant"...
I think you're trying to force in RegExp, but as someone else stated, I don't think this is the best use of regexp...

为什么不使用if（string.toUpperCase（）== string）？ ._。它更“优雅”......我认为你试图强迫RegExp，但正如其他人所说的那样，我不认为这是正则表达式的最佳用途......

#4

The string contains a lowercase letter if the expression /[a-z]/ returns true, so simply perform this check, if it's false you have no lowercase letters.

如果表达式/ [a-z] /返回true，则字符串包含小写字母，因此只需执行此检查，如果它为false，则表示没有小写字母。

#5

Simplest would seem to be:

最简单的似乎是：

^[^a-z]*$

#6

How about (s == uppercase(s)) --> string is all caps?

怎么样（s == uppercase（s）） - >字符串是全部大写？

#7

$str="ABCcDEF";
if ( preg_match ("/[a-z]/",$str ) ){
    echo "Lowercase found\n";
}

#8

If you want to match the string against another regex after making sure that there are no lower case letters, you can use positive lookahead.

如果要在确保没有小写字母后将字符串与另一个正则表达式匹配，则可以使用正向前瞻。

^(?=[^a-z]*$)MORE_REGEX$

For example, to make sure that first and last characters are alpha-numeric:

例如，要确保第一个和最后一个字符是字母数字：

^(?=[^a-z]*$)[A-Z0-9].*[A-Z0-9]$

#1

m/^[^a-z]*$/