将字符串拆分为字符串数组。

I need to split a String into an array of single character Strings.

我需要将一个字符串分割成一个字符串数组。

Eg, splitting "cat" would give the array "c", "a", "t"

例如，分裂的“猫”会给数组“c”、“a”、“t”

10 个解决方案

#1

"cat".split("(?!^)")

This will produce

这将产生

array ["c", "a", "t"]

array[“c”、“a”、“t”)

#2

"cat".toCharArray()

But if you need strings

但如果你需要字符串。

"cat".split("")

Edit: which will return an empty first value.

编辑:它将返回一个空的第一个值。

#3

String str = "cat";
char[] cArray = str.toCharArray();

#4

Take a look at the String class's getChars() method.

查看字符串类的getChars()方法。

#5

If characters beyond Basic Multilingual Plane are expected on input (some CJK characters, new emoji...), approaches such as "a????b".split("(?!^)") cannot be used, because they break such characters (results into array ["a", "?", "?", "b"]) and something safer has to be used:

如果字符超出基本多语种飞机预计输入(some CJK characters,"a????b".split("(?!^)")等新emoji...),方法不能used,因为他们这样的人物(results分解成数组["a","?",“?”而更安全的东西必须被使用:

"a????b".codePoints()
    .mapToObj(cp -> new String(Character.toChars(cp)))
    .toArray(size -> new String[size]);

#6

An efficient way of turning a String into an array of one-character Strings would be to do this:

将字符串转换成一个字符串数组的有效方法是:

String[] res = new String[str.length()];
for (int i = 0; i < str.length(); i++) {
    res[i] = Character.toString(str.charAt(i));
}

However, this does not take account of the fact that a char in a String could actually represent half of a Unicode code-point. (If the code-point is not in the BMP.) To deal with that you need to iterate through the code points ... which is more complicated.

然而，这并没有考虑到字符串中的字符实际上可以表示Unicode代码点的一半。(如果代码点不在BMP中)。要解决这个问题，您需要遍历代码点……这是更为复杂。

This approach will be faster than using String.split(/* clever regex*/), and it will probably be faster than using Java 8+ streams. It is probable faster than this:

这种方法将比使用字符串更快。split(/*巧妙的regex*/)，可能比使用Java 8+流要快。它可能比这更快:

String[] res = new String[str.length()];
int 0 = 0;
for (char ch: str.toCharArray[]) {
    res[i++] = Character.toString(ch);
}  

because toCharArray has to copy the characters to a new array.

因为toCharArray必须将字符复制到一个新的数组中。

#7

To sum up the other answers...

总结一下其他答案……

This works on all Java versions:

这适用于所有Java版本:

"cat".split("(?!^)")

This only works on Java 8 and up:

这只适用于Java 8和以上版本:

"cat".split("")

#8

If the original string contains supplementary Unicode characters, then split() would not work, as it splits these characters into surrogate pairs. To correctly handle these special characters, a code like this works:

如果原始字符串包含补充的Unicode字符，那么split()将不起作用，因为它将这些字符分割为代理对。要正确处理这些特殊字符，可以使用如下代码:

String[] chars = new String[stringToSplit.codePointCount(0, stringToSplit.length())];
for (int i = 0, j = 0; i < stringToSplit.length(); j++) {
    int cp = stringToSplit.codePointAt(i);
    char c[] = Character.toChars(cp);
    chars[j] = new String(c);
    i += Character.charCount(cp);
}

#9

Maybe you can use a for loop that goes through the String content and extract characters by characters using the charAt method.

也许您可以使用一个for循环来遍历字符串内容并使用charAt方法通过字符提取字符。

Combined with an ArrayList<String> for example you can get your array of individual characters.

例如，结合ArrayList 可以获得单个字符的数组。

#10

for(int i=0;i<str.length();i++)
{
System.out.println(str.charAt(i));
}