Possible Duplicate:
How do you split a list into evenly sized chunks in Python?可能重复：如何在Python中将列表拆分为大小均匀的块？
mylist = [1, 2, 3, 4, 5, 6, 7, 8, 9]
I need to pass blocks of these to a third party API that can only deal with 4 items at a time. I could do one at a time but it's a HTTP request and process for each go so I'd prefer to do it in the lowest possible number of queries.
我需要将这些块传递给第三方API，它一次只能处理4个项目。我可以一次做一个，但它是每个go的HTTP请求和进程，所以我更愿意在尽可能少的查询中执行。
What I'd like to do is chunk the list into blocks of four and submit each sub-block.
我想做的是将列表分成四个块并提交每个子块。
So from the above list, I'd expect:
所以从上面的列表中，我希望：
[[1, 2, 3, 4], [5, 6, 7, 8], [9]]
1 个解决方案
#1
31
mylist = [1, 2, 3, 4, 5, 6, 7, 8, 9]
print [mylist[i:i+4] for i in range(0, len(mylist), 4)]
# Prints [[1, 2, 3, 4], [5, 6, 7, 8], [9]]
#1
31
mylist = [1, 2, 3, 4, 5, 6, 7, 8, 9]
print [mylist[i:i+4] for i in range(0, len(mylist), 4)]
# Prints [[1, 2, 3, 4], [5, 6, 7, 8], [9]]