The following line of code, which creates a variable-length array on the stack:
以下代码行，在堆栈上创建一个可变长度数组:
char name[length] = {'\0'};Generates the following compiler diagnostics:
生成以下编译器诊断:
error: variable-sized object may not be initializedwarning: excess elements in array initializerwarning: (near initialization for ‘name’)What options are available to me for initializing VLAs? Am I forced to use a line such as:
对于初始化VLAs，我有什么选择?我是否*使用这样的句子:
memset(name, 0, sizeof(name));Instead?
而不是?
1 个解决方案
#1
5
Yes, you must write code for the initialisation of VLAs (which could be a memset() like you have described, or any other way that you care to).
是的，您必须为VLAs的初始化编写代码(可以是如您所描述的memset()，或者您关心的任何其他方式)。
It is simply a constraint in the C standard (§6.7.8):
它只是一个约束在C标准(§6.7.8):
- The type of the entity to be initialized shall be an array of unknown size or an object type that is not a variable length array type.
- 要初始化的实体的类型应该是未知大小的数组，或者不是可变长度数组类型的对象类型。
#1
5
Yes, you must write code for the initialisation of VLAs (which could be a memset() like you have described, or any other way that you care to).
是的，您必须为VLAs的初始化编写代码(可以是如您所描述的memset()，或者您关心的任何其他方式)。
It is simply a constraint in the C standard (§6.7.8):
它只是一个约束在C标准(§6.7.8):
- The type of the entity to be initialized shall be an array of unknown size or an object type that is not a variable length array type.
- 要初始化的实体的类型应该是未知大小的数组，或者不是可变长度数组类型的对象类型。