numpy：创建一个2d numpy数组，其中每行用常规数组中的字符串填充

I have a regular list filled with strings of equal length:

我有一个常规列表,其中填充了相同长度的字符串:

['FADVAG', 'XXDXFA', 'GDXX..']

I want to transform it into a 2d numpy array, like the following:

我想将它转换为2d numpy数组,如下所示:

[['F' 'A' 'D' 'V' 'A' 'G']
['X' 'X' 'D' 'X' 'F' 'A']
['G' 'D' 'X' 'X' '.' '.']]

How can I do that?

我怎样才能做到这一点?

2 个解决方案

#1

list('astring') splits up the characters:

list('astring')拆分字符:

In [187]: alist=['FADVAG', 'XXDXFA', 'GDXX..']
In [188]: arr = np.array([list(a) for a in alist])
In [189]: arr
Out[189]: 
array([['F', 'A', 'D', 'V', 'A', 'G'],
       ['X', 'X', 'D', 'X', 'F', 'A'],
       ['G', 'D', 'X', 'X', '.', '.']],
      dtype='<U1')

If you want to avoid a list comprehension, join them into one string and go from there

如果您想避免列表理解,请将它们连接成一个字符串并从那里开始

np.array(list(''.join(alist))).reshape(3,-1)

#2

try below code:

尝试下面的代码:

import numpy as np
l = ['FADVAG', 'XXDXFA', 'GDXX..']
l = np.array(l)
l.reshape(len(l),-1)

output:

array([['FADVAG'],
       ['XXDXFA'],
       ['GDXX..']],
      dtype='<U6')

#1