不使用+符号添加两个数字[重复]

This question already has an answer here:

这个问题在这里已有答案:

What is the best way to add two numbers without using the + operator? 20 answers

不使用+运算符添加两个数字的最佳方法是什么? 20个答案

I am 9 grade, My math teacher asked me to add numbers with out using + sign in C program.

我9年级,我的数学老师让我在C程序中使用+符号添加数字。

I tried a - (-b) = a + b; but my math teacher want some other option.

我试过 - (-b)= a + b;但我的数学老师想要一些其他选择。

5 个解决方案

#1

Using Anti Log() you can do that

使用Anti Log()可以做到这一点

Temp= Anti Log(a)* Anti Log(b);

a+b value is equals to log(Temp);

Works for integers not for double.

适用于不是双精度的整数。

#2

Use this function in your c program

在c程序中使用此功能

int Add(int a, int b)
{
    while (b)
    {
        // carry now contains common set bits of "a" and "b"
        int carry = a & b;

        // Sum of bits of "a" and "b" where at least one of the bits is not set
        a = a ^ b;

        // Carry is shifted by one so that adding it to "a" gives the required sum
        b = carry << 1;
    }
    return a;
}

#3

Use bitwise ^ and & operators and recursion

使用按位^和&运算符和递归

int add(int x, int y){
    return y == 0 ? x : add( x ^ y, (x & y) << 1);
}

P.S.: It is the recursive version of an algorithm proposed by vikas.

P.S。:它是vikas提出的算法的递归版本。

#4

In Java using recursion-

在Java中使用递归 -

public static int add(int a, int b){

    if(b == 0) return a;
    int sum = a ^ b;
    int carry = (a & b) << 1;

    return add(sum, carry);

}

In C-

int add(int a, int b){

    if(b == 0) return a;
    int sum = a ^ b;
    int carry = (a & b) << 1;

    return add(sum, carry);
}

#5

#include<stdio.h>

int add(int a, int b) {
    return (int)&((char *)a)[b];
}

int main() {
    printf("%d", add(5, 17));
    getchar();
}

Not portable but doesn't use the "+" character. This casts a to a char pointer, adds b to it with [] and then casts it back to an int.

不可携带,但不使用“+”字符。这会将a转换为char指针,使用[]向其添加b,然后将其强制转换为int。

#1