I got results for both dividing substrings and replacing multiple substrings using map array. I would like to split a string with n-length before its substrings are replaced
我得到了分割子串的结果,并使用map数组替换了多个子串。我想在替换子串之前拆分一个n长的字符串
Eg: AABBCCDDEE
例如:AABBCCDDEE
MapArray : {
AA: A,
AB: B, <<<< this
BB: F,
CC: C,
DD: D,
EE: E
}
Result : AFCDE
结果:AFCDE
I need the string to be split with length 2, so that the code won't replace 'AB', instead of replacing 'AA' and 'BB' seperately.
I can explain more if needed! Thanks in advance!
我需要将字符串拆分为长度为2,这样代码就不会替换'AB',而是单独替换'AA'和'BB'。如果需要,我可以解释更多!提前致谢!
1 个解决方案
#1
1
The code to split the string into parts of 2 character length comes from here, then it applies the map and outputs the resulting string.
将字符串拆分为2个字符长度的部分的代码来自此处,然后它应用地图并输出结果字符串。
var mapArray = {
AA: 'A',
AB: 'B',
BB: 'F',
CC: 'C',
DD: 'D',
EE: 'E'
};
var inp = "AABBCCDDEEX";
var out = inp.match(/.{1,2}/g).map(a => mapArray[a] || "-").join('');
console.log(out);
#1
1
The code to split the string into parts of 2 character length comes from here, then it applies the map and outputs the resulting string.
将字符串拆分为2个字符长度的部分的代码来自此处,然后它应用地图并输出结果字符串。
var mapArray = {
AA: 'A',
AB: 'B',
BB: 'F',
CC: 'C',
DD: 'D',
EE: 'E'
};
var inp = "AABBCCDDEEX";
var out = inp.match(/.{1,2}/g).map(a => mapArray[a] || "-").join('');
console.log(out);