Please read this question carefully before down voting. I could not find my problem in other questions here.
请在投票前仔细阅读这个问题。我在其他问题中找不到我的问题。
Suppose I have an array,
假设我有一个数组,
>>> import numpy as np
>>> array = np.linspace(1,4,4, dtype=np.int)
>>> array
array([1, 2, 3, 4])
I want a function that will split this array in all possible parts, such that,
我想要一个函数把这个数组分成所有可能的部分,这样,
No split :
没有分割:
([1,2,3,4])
Split in 2
parts :
分为两部分:
([1], [2,3,4])
([1,2], [3,4])
([1,2,3] ,[4])
Split in 3
parts :
分三部分:
([1], [2], [3,4])
([1,2]), [3], [4])
([1], [2,3], [4])
Split in len(array)
parts :
分割为len(数组)部分:
([1],[2],[3],[4])
I know there is np.split(array, r)
, but it will not give all possible splits. e.g. np.split(array, 2)
will give,
我知道有np。分割(数组,r),但它不会给出所有可能的分割。例如np。分裂(数组,2)会给,
[array([0, 1]), array([2, 3])]
As you can see this is not what I need. How to achieve my need?
正如你所看到的,这不是我所需要的。如何实现我的需求?
2 个解决方案
#1
3
You could use itertools.combinations
to generate the indices where to split inside a loop over the number of splits:
您可以使用itertools.combination来生成索引,在循环中对分割的数量进行分割:
>>> from itertools import combinations
>>> [np.split(array, idx)
... for n_splits in range(5)
... for idx in combinations(range(1, len(array)), n_splits)]
[[array([1, 2, 3, 4])],
[array([1]), array([2, 3, 4])],
[array([1, 2]), array([3, 4])],
[array([1, 2, 3]), array([4])],
[array([1]), array([2]), array([3, 4])],
[array([1]), array([2, 3]), array([4])],
[array([1, 2]), array([3]), array([4])],
[array([1]), array([2]), array([3]), array([4])]]
#2
2
not familiar with numpy, but you can do it in pure python using divide and conquer(whether split on this position or not ):
不熟悉numpy,但是可以在纯python中使用divide and conquer(无论是否在这个位置上拆分):
def split(a):
if not a:
return [[]]
elif len(a) == 1:
return [[a]]
else:
result = []
for i in range(1, len(a) + 1):
result += [(a[:i], *sub_split) for sub_split in split(a[i:])]
return result
split([1,2,3])
# output => [([1], [2], [3]), ([1], [2, 3]), ([1, 2], [3]), ([1, 2, 3],)]
#1
3
You could use itertools.combinations
to generate the indices where to split inside a loop over the number of splits:
您可以使用itertools.combination来生成索引,在循环中对分割的数量进行分割:
>>> from itertools import combinations
>>> [np.split(array, idx)
... for n_splits in range(5)
... for idx in combinations(range(1, len(array)), n_splits)]
[[array([1, 2, 3, 4])],
[array([1]), array([2, 3, 4])],
[array([1, 2]), array([3, 4])],
[array([1, 2, 3]), array([4])],
[array([1]), array([2]), array([3, 4])],
[array([1]), array([2, 3]), array([4])],
[array([1, 2]), array([3]), array([4])],
[array([1]), array([2]), array([3]), array([4])]]
#2
2
not familiar with numpy, but you can do it in pure python using divide and conquer(whether split on this position or not ):
不熟悉numpy,但是可以在纯python中使用divide and conquer(无论是否在这个位置上拆分):
def split(a):
if not a:
return [[]]
elif len(a) == 1:
return [[a]]
else:
result = []
for i in range(1, len(a) + 1):
result += [(a[:i], *sub_split) for sub_split in split(a[i:])]
return result
split([1,2,3])
# output => [([1], [2], [3]), ([1], [2, 3]), ([1, 2], [3]), ([1, 2, 3],)]