$arr = array('1st', '1st');
The above $arr has 2 items , I want to repeat $arr so that it's populated with 4 items
上面的$ arr有2个项目,我想重复$ arr,以便填充4个项目
Is there a single call in PHP?
在PHP中有一个单独的调用吗?
3 个解决方案
#1
10
array_fill function should help:
array_fill函数应该有帮助:
array array_fill ( int $start_index, int $num, mixed $value )
Fills an array with num entries of the value of the value parameter, keys starting at the start_index parameter.
使用value参数值的num个条目填充数组,从start_index参数开始的键。
In your case code will look like:
在您的情况下代码将如下所示:
$arr = array_fill(0, 4, '1st');
#2
8
$arr = array('1st', '1st');
$arr = array_merge($arr, $arr);
#3
0
This is a more general answer. In PHP 5.6+ you can use the "splat" operator (...) to repeat the array an arbitrary number of times:
这是一个更一般的答案。在PHP 5.6+中,您可以使用“splat”运算符(...)重复数组任意次:
array_merge(...array_fill(0, $n, $arr));
Where $n is any integer.
其中$ n是任何整数。
#1
10
array_fill function should help:
array_fill函数应该有帮助:
array array_fill ( int $start_index, int $num, mixed $value )
Fills an array with num entries of the value of the value parameter, keys starting at the start_index parameter.
使用value参数值的num个条目填充数组,从start_index参数开始的键。
In your case code will look like:
在您的情况下代码将如下所示:
$arr = array_fill(0, 4, '1st');
#2
8
$arr = array('1st', '1st');
$arr = array_merge($arr, $arr);
#3
0
This is a more general answer. In PHP 5.6+ you can use the "splat" operator (...) to repeat the array an arbitrary number of times:
这是一个更一般的答案。在PHP 5.6+中,您可以使用“splat”运算符(...)重复数组任意次:
array_merge(...array_fill(0, $n, $arr));
Where $n is any integer.
其中$ n是任何整数。