使用String.split()和多个分隔符

I need to split a string base on delimiter - and .. Below are my desired output.

我需要在分隔符的基础上分割一个字符串。下面是我想要的输出。

AA.BB-CC-DD.zip ->

AA.BB-CC-DD。zip - >

AA
BB
CC
DD
zip

but my following code does not work.

但是我下面的代码不起作用。

private void getId(String pdfName){
    String[]tokens = pdfName.split("-\\.");
}

11 个解决方案

#1

248

I think you need to include the regex OR operator:

我认为您需要包含regex或操作符:

String[]tokens = pdfName.split("-|\\.");

What you have will match "-." not a "-" or a "."

你所拥有的将是匹配的"-."而不是"-"或" a "。"

#2

Try this regex "[-.]+". The + after treats consecutive delimiter chars as one. Remove plus if you do not want this.

试试这个正则表达式“(-)+”。+将连续分隔符chars视为一个。如果你不想要这个，就删除它。

#3

You can use the regex "\W".This matches any non-word character.The required line would be:

您可以使用regex“\W”。这匹配任何非文字字符。所需的线是:

String[] tokens=pdfName.split("\\W");

#4

Using Guava you could do this:

你可以用番石榴:

Iterable<String> tokens = Splitter.on(CharMatcher.anyOf("-.")).split(pdfName);

#5

The string you give split is the string form of a regular expression, so:

你给split的字符串是正则表达式的字符串形式，因此:

private void getId(String pdfName){
    String[]tokens = pdfName.split("[\\-.]");
}

That means to split on any character in the [] (we have to escape - with a backslash because it's special inside []; and of course we have to escape the backslash because this is a string). (Conversely, . is normally special but isn't special inside [].)

这意味着在[]中分割任何字符(我们必须转义——使用反斜杠，因为它在[]内部是特殊的;当然，我们必须转义反斜杠，因为这是一个字符串)。(相反的,。通常是特殊的，但在内部并不特殊。

#6

I'd use Apache Commons:

我使用Apache Commons:

import org.apache.commons.lang3.StringUtils;

进口org.apache.commons.lang3.StringUtils;

private void getId(String pdfName){
    String[] tokens = StringUtils.split(pdfName, "-.");
}

It'll split on any of the specified separators, as opposed to StringUtils.splitByWholeSeparator(str, separator) which uses the complete string as a separator

它将在任何指定的分隔符上分割，而不是StringUtils。splitbyproduceparator (str，分隔符)，它使用完整的字符串作为分隔符。

#7

You may also specified regular expression as argument in split() method ..see below example....

您还可以在split()方法中将正则表达式指定为参数。参见下面的例子....

private void getId(String pdfName){
String[]tokens = pdfName.split("-|\\.");
}

#8

It's better to use something like this:

最好是这样:

s.split("[\\s\\-\\.\\'\\?\\,\\_\\@]+");

Have added a few other characters as sample. This is the safest way to use, because the way . and ' is treated.

添加了一些其他字符作为示例。这是最安全的使用方法，因为这个方法。和“治疗。

#9

s.trim().split("[\\W]+")

should work.

应该工作。

#10

For two char sequence as delimeters "AND" and "OR" this should be worked. Don't forget to trim while using.

对于两个字符序列，如“delimeter”和“AND”或“this should be working”。使用时别忘了修剪。

 String text ="ISTANBUL AND NEW YORK AND PARIS OR TOKYO AND MOSCOW";
 String[] cities = text.split("AND|OR");

Result : cities = {"ISTANBUL ", " NEW YORK ", " PARIS ", " TOKYO ", " MOSCOW"}

结果:城市={“伊斯坦布尔”、“纽约”、“巴黎”、“东京”、“莫斯科”}

#11

-1

If you know the sting will always be in the same format, first split the string based on . and store the string at the first index in a variable. Then split the string in the second index based on - and store indexes 0, 1 and 2. Finally, split index 2 of the previous array based on . and you should have obtained all of the relevant fields.

如果您知道sting将始终保持相同的格式，那么首先根据这个格式拆分字符串。并将字符串存储在变量的第一个索引中。然后根据-和存储索引0,1和2将字符串分割到第二个索引中。最后，根据前面的数组分割索引2。你应该得到所有相关的字段。

Refer to the following snippet:

请参阅以下片段:

String[] tmp = pdfName.split(".");
String val1 = tmp[0];
tmp = tmp[1].split("-");
String val2 = tmp[0];
...

#1

248