I have this string
我有这个字符串
'john smith~123 Street~Apt 4~New York~NY~12345'
Using JavaScript, what is the fastest way to parse this into
使用JavaScript,最快的解析方法是什么
var name = "john smith";
var street= "123 Street";
//etc...
11 个解决方案
#1
702
With JavaScript’s String.prototype.split
function:
JavaScript的String.prototype。拆分功能:
var input = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = input.split('~');
var name = fields[0];
var street = fields[1];
// etc.
#2
44
You don't need jQuery.
你不需要jQuery。
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
#3
15
Even though this is not the simplest way, you could do this:
尽管这不是最简单的方法,但你可以这样做:
var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
keys = "name address1 address2 city state zipcode".split(" "),
address = {};
// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
address[ keys.unshift() ] = match;
});
// address will contain the mapped result
address = {
address1: "123 Street"
address2: "Apt 4"
city: "New York"
name: "john smith"
state: "NY"
zipcode: "12345"
}
Update for ES2015, using destructuring
更新ES2015,使用解构
const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);
// The variables defined above now contain the appropriate information:
console.log(address1, address2, city, name, state, zipcode);
// -> john smith 123 Street Apt 4 New York NY 12345
#4
14
According to ECMAScript6 ES6
, the clean way is destructing arrays:
根据ECMAScript6 ES6,干净的方式是破坏数组:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';
const [name, street, unit, city, state, zip] = input.split('~');
console.log(name); // john smith
console.log(street); // 123 Street
console.log(unit); // Apt 4
console.log(city); // New York
console.log(state); // NY
console.log(zip); // 12345
You may have extra items in the input string. In this case, you can use rest operator to get an array for the rest or just ignore them:
您可能在输入字符串中有额外的项。在这种情况下,可以使用rest操作符获取剩余的数组,或者忽略它们:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';
const [name, street, ...others] = input.split('~');
console.log(name); // john smith
console.log(street); // 123 Street
console.log(others); // ["Apt 4", "New York", "NY", "12345"]
I supposed a read-only reference for values and used the const
declaration.
我假设值为只读引用,并使用const声明。
Enjoy ES6!
享受ES6 !
#5
#6
5
well, easiest way would be something like:
最简单的方法是
var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
#7
5
If Spliter is found then only
如果是拆分器,则只找到
Split it
把它
else return the same string
否则返回相同的字符串
function SplitTheString(ResultStr) { if (ResultStr != null) { var SplitChars = '~'; if (ResultStr.indexOf(SplitChars) >= 0) { var DtlStr = ResultStr.split(SplitChars); var name = DtlStr[0]; var street = DtlStr[1]; } } }
#8
4
Something like:
喜欢的东西:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
可能最简单?
#9
3
You can use split
to split the text.
可以使用split来拆分文本。
As an alternative, you can also use match
as follow
作为一种选择,您也可以使用match作为follow。
var str = 'john smith~123 Street~Apt 4~New York~NY~12345';
matches = str.match(/[^~]+/g);
console.log(matches);
document.write(matches);
The regex [^~]+
will match all the characters except ~
and return the matches in an array. You can then extract the matches from it.
regex ^ ~ +将匹配所有的人物除了~并返回匹配数组中。然后可以从中提取匹配项。
#10
2
Zach had this one right.. using his method you could also make a seemingly "multi-dimensional" array.. I created a quick example at JSFiddle http://jsfiddle.net/LcnvJ/2/
扎克说得对。使用他的方法,你也可以制作一个看似“多维”的数组。我在JSFiddle http://jsfiddle.net/LcnvJ/2/创建了一个快速示例
// array[0][0] will produce brian
// array[0][1] will produce james
// array[1][0] will produce kevin
// array[1][1] will produce haley
var array = [];
array[0] = "brian,james,doug".split(",");
array[1] = "kevin,haley,steph".split(",");
#11
0
Use this code------
使用这个代码- - - - - -
function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");
}
#1
702
With JavaScript’s String.prototype.split
function:
JavaScript的String.prototype。拆分功能:
var input = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = input.split('~');
var name = fields[0];
var street = fields[1];
// etc.
#2
44
You don't need jQuery.
你不需要jQuery。
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
#3
15
Even though this is not the simplest way, you could do this:
尽管这不是最简单的方法,但你可以这样做:
var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
keys = "name address1 address2 city state zipcode".split(" "),
address = {};
// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
address[ keys.unshift() ] = match;
});
// address will contain the mapped result
address = {
address1: "123 Street"
address2: "Apt 4"
city: "New York"
name: "john smith"
state: "NY"
zipcode: "12345"
}
Update for ES2015, using destructuring
更新ES2015,使用解构
const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);
// The variables defined above now contain the appropriate information:
console.log(address1, address2, city, name, state, zipcode);
// -> john smith 123 Street Apt 4 New York NY 12345
#4
14
According to ECMAScript6 ES6
, the clean way is destructing arrays:
根据ECMAScript6 ES6,干净的方式是破坏数组:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';
const [name, street, unit, city, state, zip] = input.split('~');
console.log(name); // john smith
console.log(street); // 123 Street
console.log(unit); // Apt 4
console.log(city); // New York
console.log(state); // NY
console.log(zip); // 12345
You may have extra items in the input string. In this case, you can use rest operator to get an array for the rest or just ignore them:
您可能在输入字符串中有额外的项。在这种情况下,可以使用rest操作符获取剩余的数组,或者忽略它们:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';
const [name, street, ...others] = input.split('~');
console.log(name); // john smith
console.log(street); // 123 Street
console.log(others); // ["Apt 4", "New York", "NY", "12345"]
I supposed a read-only reference for values and used the const
declaration.
我假设值为只读引用,并使用const声明。
Enjoy ES6!
享受ES6 !
#5
12
You'll want to look into JavaScript's substr or split as this is not really a task suited for jQuery
您需要查看JavaScript的substr或split,因为这并不是真正适合jQuery的任务。
#6
5
well, easiest way would be something like:
最简单的方法是
var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
#7
5
If Spliter is found then only
如果是拆分器,则只找到
Split it
把它
else return the same string
否则返回相同的字符串
function SplitTheString(ResultStr) { if (ResultStr != null) { var SplitChars = '~'; if (ResultStr.indexOf(SplitChars) >= 0) { var DtlStr = ResultStr.split(SplitChars); var name = DtlStr[0]; var street = DtlStr[1]; } } }
#8
4
Something like:
喜欢的东西:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
可能最简单?
#9
3
You can use split
to split the text.
可以使用split来拆分文本。
As an alternative, you can also use match
as follow
作为一种选择,您也可以使用match作为follow。
var str = 'john smith~123 Street~Apt 4~New York~NY~12345';
matches = str.match(/[^~]+/g);
console.log(matches);
document.write(matches);
The regex [^~]+
will match all the characters except ~
and return the matches in an array. You can then extract the matches from it.
regex ^ ~ +将匹配所有的人物除了~并返回匹配数组中。然后可以从中提取匹配项。
#10
2
Zach had this one right.. using his method you could also make a seemingly "multi-dimensional" array.. I created a quick example at JSFiddle http://jsfiddle.net/LcnvJ/2/
扎克说得对。使用他的方法,你也可以制作一个看似“多维”的数组。我在JSFiddle http://jsfiddle.net/LcnvJ/2/创建了一个快速示例
// array[0][0] will produce brian
// array[0][1] will produce james
// array[1][0] will produce kevin
// array[1][1] will produce haley
var array = [];
array[0] = "brian,james,doug".split(",");
array[1] = "kevin,haley,steph".split(",");
#11
0
Use this code------
使用这个代码- - - - - -
function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");
}