This works
这是
x <- "0.466:1.187:2.216:1.196"
y <- as.numeric(unlist(strsplit(x, ":")))
Values of blat$LRwAvg
all look like X
above but this doesn't work
blat$LRwAvg的值看起来都像上面的X,但这不起作用
for (i in 1:50){
y <- as.numeric(unlist(strsplit(blat$LRwAvg[i], "\\:")))
blat$meanLRwAvg[i]=mean(y)
}
Because of:
因为:
Error in strsplit(blat$LRwAvg[i], "\:") : non-character argument
strsplit(blat$LRwAvg[i],“\:”)中的错误:非字符参数
It doesn't matter if I have one, two or null backslashes.
不管我有一个,两个还是零反斜杠。
What's my problem? (Not generally, I mean in this special task, technically)
我的问题是什么?(我的意思是在这个特殊的任务中,技术上不是一般的)
1 个解决方案
#1
19
As agstudy implied blat$LRwAvg <- as.character(blat$LRwAvg)
before loop fixed it
正如agstudy在loop修复之前暗示blat$LRwAvg <- As .character(blat$LRwAvg)
blat$meanLRwAvg <- blat$gtFrqAvg #or some other variable in data frame with equal length
blat$LRwAvg <- as.character(blat$LRwAvg)
for (i in 1:50){
y <- as.numeric(unlist(strsplit(blat$LRwAvg[i], "\\:")))
blat$meanLRwAvg[i]=mean(y)
}
#1
19
As agstudy implied blat$LRwAvg <- as.character(blat$LRwAvg)
before loop fixed it
正如agstudy在loop修复之前暗示blat$LRwAvg <- As .character(blat$LRwAvg)
blat$meanLRwAvg <- blat$gtFrqAvg #or some other variable in data frame with equal length
blat$LRwAvg <- as.character(blat$LRwAvg)
for (i in 1:50){
y <- as.numeric(unlist(strsplit(blat$LRwAvg[i], "\\:")))
blat$meanLRwAvg[i]=mean(y)
}