From a function I am given a multidimensional array like this:
从函数我得到一个像这样的多维数组:
array(
[0] => array(
[0] => 7,
[1] => 18
),
[1] => array(
[0] => 12,
[1] => 7
),
[2] => array(
[0] => 12,
[1] => 7,
[2] => 13
)
)
I need to find duplicate values in the 3 arrays within the main array. For example, if value 7 repeats in the 3 arrays, return 7.
我需要在主数组中的3个数组中找到重复值。例如,如果值3在3个数组中重复,则返回7。
4 个解决方案
#1
7
<?php
$array = array(array(7,18), array(12,7), array(12, 7, 13));
$result = array();
$first = $array[0];
for($i=1; $i<count($array); $i++){
$result = array_intersect ($first, $array[$i]);
$first = $result;
}
print_r($result);//7
?>
#2
2
use my custom function
使用我的自定义功能
function array_icount_values($arr,$lower=true) {
$arr2=array();
if(!is_array($arr['0'])){$arr=array($arr);}
foreach($arr as $k=> $v){
foreach($v as $v2){
if($lower==true) {$v2=strtolower($v2);}
if(!isset($arr2[$v2])){
$arr2[$v2]=1;
}else{
$arr2[$v2]++;
}
}
}
return $arr2;
}
$arr = array_icount_values($arry);
echo "<pre>";
print_r($arr);
exit;
OUPUT
Array
(
[7] => 3
[18] => 1
[12] => 2
[13] => 1
)
hope this will sure help you.
希望这一定会对你有所帮助。
#3
1
$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input);
print_r($result);
use this code
使用此代码
$array = array(0 => 'blue', 1 => 'red', 2 => 'green', 3 => 'red');
$key = array_search('green', $array); // $key = 2;
$ key = array_search('green',$ array); // $ key = 2;
#4
1
You will need to loop through the first array, and for each value in it, see if it is in_array().
您将需要循环遍历第一个数组,并为其中的每个值查看它是否为in_array()。
$findme = array();
foreach ($array[0] as $key => $value)
{
if (in_array ($value, $array[1]) && in_array ($value, $array[2]))
{
$findme[] = $value;
}
}
// $findme will be an array containing all values that are present in all three arrays (if any).
#1
7
<?php
$array = array(array(7,18), array(12,7), array(12, 7, 13));
$result = array();
$first = $array[0];
for($i=1; $i<count($array); $i++){
$result = array_intersect ($first, $array[$i]);
$first = $result;
}
print_r($result);//7
?>
#2
2
use my custom function
使用我的自定义功能
function array_icount_values($arr,$lower=true) {
$arr2=array();
if(!is_array($arr['0'])){$arr=array($arr);}
foreach($arr as $k=> $v){
foreach($v as $v2){
if($lower==true) {$v2=strtolower($v2);}
if(!isset($arr2[$v2])){
$arr2[$v2]=1;
}else{
$arr2[$v2]++;
}
}
}
return $arr2;
}
$arr = array_icount_values($arry);
echo "<pre>";
print_r($arr);
exit;
OUPUT
Array
(
[7] => 3
[18] => 1
[12] => 2
[13] => 1
)
hope this will sure help you.
希望这一定会对你有所帮助。
#3
1
$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input);
print_r($result);
use this code
使用此代码
$array = array(0 => 'blue', 1 => 'red', 2 => 'green', 3 => 'red');
$key = array_search('green', $array); // $key = 2;
$ key = array_search('green',$ array); // $ key = 2;
#4
1
You will need to loop through the first array, and for each value in it, see if it is in_array().
您将需要循环遍历第一个数组,并为其中的每个值查看它是否为in_array()。
$findme = array();
foreach ($array[0] as $key => $value)
{
if (in_array ($value, $array[1]) && in_array ($value, $array[2]))
{
$findme[] = $value;
}
}
// $findme will be an array containing all values that are present in all three arrays (if any).