如何在C ++中返回二维数组

时间:2021-09-06 21:38:24

I am trying to implement a Matrix4x4 class for my port of 3D Engine that I had made earlier. Here is what I have so far in my header file:

我正在尝试为我之前制作的3D引擎端口实现Matrix4x4类。这是我目前在头文件中的内容:

#ifndef MAT4_H
#define MAT4_H

class Matrix4
{

public:
   Matrix4() {}
   float[4][4] getMatrix() { return m; }
   //...
   //other matrix related methods are omitted
   //...
private:
   float m[4][4]; 

};

#endif

But the method that is supposed to return the two-dimensional array causes this error:

但是应该返回二维数组的方法会导致此错误:

src/Matrix4.h:13:10: error: expected unqualified-id before '[' token
    float[4][4] getMatrix() { return m; }
         ^

I am sorry if this question already has an answer, but the answers that I found on this site were usually about returning pointers instead of an array. Hope you can help, thanks.

我很抱歉,如果这个问题已经有了答案,但我在这个网站上找到的答案通常是关于返回指针而不是数组。希望你能帮忙,谢谢。

3 个解决方案

#1


9  

I would suggest to use std::array. But using it directly in code, as multi array, is a bit ugly. So I'd suggest an alias, defined as:

我建议使用std :: array。但是直接在代码中使用它作为多数组,有点难看。所以我建议别名,定义为:

#include <array> 

namespace details 
{    
   template<typename T, std::size_t D, std::size_t ... Ds> 
   struct make_multi_array 
    : make_multi_array<typename make_multi_array<T,Ds...>::type, D> {}; 

   template<typename T, std::size_t D>
   struct make_multi_array<T,D> { using type = std::array<T, D>;  };
}

template<typename T, std::size_t D, std::size_t  ... Ds> 
using multi_array = typename details::make_multi_array<T,D,Ds...>::type;

Then use it as:

然后用它作为:

public:

   multi_array<float,4,4> getMatrix() { return m; }

private:
   multi_array<float,4,4> m;

You could use the alias in other places as well, such as:

您也可以在其他地方使用别名,例如:

 //same as std::array<int,10> 
 //similar to int x[10] 
 multi_array<int,10>   x;   

 //same as std::array<std::array<int,20>,10>
 //similar to int y[10][20] 
 multi_array<int,10,20> y;   

 //same as std::array<std::array<std::array<int,30>,20>,10>
 //similar to int z[10][20][30]
 multi_array<int,10,20,30> z; 

Hope that helps.

希望有所帮助。

#2


0  

Passing an array in either C or C++ is possible by a passing pointer to its first element- the pointer is passed by value.

通过指向其第一个元素的指针,可以在C或C ++中传递数组 - 指针通过值传递。

The only way to pass your array by value would be to encapsulate it in a struct, but in most cases its better to pass a pointer then to copy all the data by value.

按值传递数组的唯一方法是将其封装在结构中,但在大多数情况下最好传递指针然后按值复制所有数据。

#3


-1  

Just return a pointer to the first element of the array! :)

只需返回指向数组第一个元素的指针! :)

#1


9  

I would suggest to use std::array. But using it directly in code, as multi array, is a bit ugly. So I'd suggest an alias, defined as:

我建议使用std :: array。但是直接在代码中使用它作为多数组,有点难看。所以我建议别名,定义为:

#include <array> 

namespace details 
{    
   template<typename T, std::size_t D, std::size_t ... Ds> 
   struct make_multi_array 
    : make_multi_array<typename make_multi_array<T,Ds...>::type, D> {}; 

   template<typename T, std::size_t D>
   struct make_multi_array<T,D> { using type = std::array<T, D>;  };
}

template<typename T, std::size_t D, std::size_t  ... Ds> 
using multi_array = typename details::make_multi_array<T,D,Ds...>::type;

Then use it as:

然后用它作为:

public:

   multi_array<float,4,4> getMatrix() { return m; }

private:
   multi_array<float,4,4> m;

You could use the alias in other places as well, such as:

您也可以在其他地方使用别名,例如:

 //same as std::array<int,10> 
 //similar to int x[10] 
 multi_array<int,10>   x;   

 //same as std::array<std::array<int,20>,10>
 //similar to int y[10][20] 
 multi_array<int,10,20> y;   

 //same as std::array<std::array<std::array<int,30>,20>,10>
 //similar to int z[10][20][30]
 multi_array<int,10,20,30> z; 

Hope that helps.

希望有所帮助。

#2


0  

Passing an array in either C or C++ is possible by a passing pointer to its first element- the pointer is passed by value.

通过指向其第一个元素的指针,可以在C或C ++中传递数组 - 指针通过值传递。

The only way to pass your array by value would be to encapsulate it in a struct, but in most cases its better to pass a pointer then to copy all the data by value.

按值传递数组的唯一方法是将其封装在结构中,但在大多数情况下最好传递指针然后按值复制所有数据。

#3


-1  

Just return a pointer to the first element of the array! :)

只需返回指向数组第一个元素的指针! :)