尝试使用Java中的regex从日志文件中获取一些有用的数据

I'm having trouble with regex, because I can only match some of my goals.

我正在使用正则表达式,因为我只能匹配我的一些目标。

I have a log file and I must match some of the items and write another txt file. I wrote a Java code for a short example of my code but when I put the whole file, everything gets messed up.

我有一个日志文件,我必须匹配一些项目,并写入另一个文本文件。我为我的代码的一个简短例子编写了一个Java代码,但是当我放入整个文件时,一切都搞砸了。

*052511 074217 0065            02242806000      UNKNOWN         U G

*052511 074217 0065    4874    02242806000      UNKNOWN         U A

*052511 074218 0065    4874    02242806000      UNKNOWN         U R

--------   05/25/11   07:42:17   LINE = 0065   STN = 4874    

   CALLING NUMBER   02242806000

   NAME             UNKNOWN        

   UNKNOWN

   BC = SPEECH

00:00:00   INCOMING CALL    RINGING 0:02

00:00:11   CALL RELEASED

I have to find these results from the file:

我必须从文件中找到这些结果:

incomming,05/25/11,07:42:17,0065,4874,02242806000,00:00:09,2

In this expression 00:00:09 means [00:00:11-00:00:00]-0:02

在这个表达式中,00:00:09表示[00:00:11-00:00:00] -0:02

For every incoming and outgoing calls, I must make the conversation above.

对于每个来电和去电,我必须进行上述对话。

Here is my code

这是我的代码

Here is the log file

这是日志文件

1 个解决方案

#1

You could use a regex like:

您可以使用正则表达式:

(?xm:
^-------- \s+ (\S+) \s+ (\S+) \s+ LINE\s*=\s*(\d+) \s+ STN\s*=\s*(\d+)
\s+ CALLING\ NUMBER \s+ (\d+) \s*
(?:^(?:[ \t]+.*)?[\n\r]+)* # eat unwanted part

^(\d\d:\d\d:\d\d) \s+ INCOMING\ CALL \s+ RINGING\ ([\d:]+) \s*
(?:^\d.*[\r\n]+)* # possible stuff
^(\d\d:\d\d:\d\d) \s+ CALL\ RELEASED
)

Use the values of the capturing groups to get your results. You may need to remove the /x related things like comments and spaces.

使用捕获组的值来获取结果。您可能需要删除/ x相关的内容,如注释和空格。

Perl example at http://ideone.com/qTBFe

在http://ideone.com/qTBFe上的Perl示例

#1