I am using the range()
function to create an array. However, I want the keys
to be the same as the value
. This is ok when i do range(0, 10)
as the index starts from 0
, however if i do range(1, 11)
, the index will still start from 0
, so it ends up 0=>1
when i want it to be 1=>1
我使用range()函数创建一个数组。但是,我希望键与值相同。当我做区间(0,10)时,这是可以的,当索引从0开始时,但是如果我做区间(1,11),索引仍然从0开始,所以当我想让它为1=>1时,它最后还是0=>1
How can I use range()
to create an array where the key
is the same as the value
?
如何使用range()创建键与值相同的数组?
6 个解决方案
#1
123
How about array_combine?
合二为一呢?
$b = array_combine(range(1,10), range(1,10));
#2
5
Or you did it this way:
或者你是这样做的:
$b = array_slice(range(0,10), 1, NULL, TRUE);
Find the output here: http://codepad.org/gx9QH7ES
在这里找到输出:http://codepad.org/gx9QH7ES
#3
1
There is no out of the box solution for this. You will have to create the array yourself, like so:
这个问题没有现成的解决方案。您必须自己创建数组,如下所示:
$temp = array();
foreach(range(1, 11) as $n) {
$temp[$n] = $n;
}
But, more importantly, why do you need this? You can just use the value itself?
但是,更重要的是,为什么你需要这个?你可以只使用值本身?
#4
0
<?php
function createArray($start, $end){
$arr = array();
foreach(range($start, $end) as $number){
$arr[$number] = $number;
}
return $arr;
}
print_r(createArray(1, 10));
?>
See output here: http://codepad.org/Z4lFSyMy
看到输出:http://codepad.org/Z4lFSyMy
#5
0
<?php
$array = array();
foreach (range(1,11) as $r)
$array[$r] = $r;
print_r($array);
?>
#6
0
Create a function to make this:
创建一个函数来实现以下目标:
if (! function_exists('sequence_equal'))
{
function sequence_equal($low, $hight, $step = 1)
{
return array_combine($range = range($low, $hight, $step), $range);
}
}
Using:
使用:
print_r(sequence_equal(1, 10, 2));
Output:
输出:
array (
1 => 1,
3 => 3,
5 => 5,
7 => 7,
9 => 9,
)
In PHP 5.5 >= you can use Generator to make this:
在PHP 5.5 >=中,您可以使用生成器来实现:
function sequence_equal($low, $hight, $step = 1)
{
for ($i = $low; $i < $hight; $i += $step) {
yield $i => $i;
}
}
#1
123
How about array_combine?
合二为一呢?
$b = array_combine(range(1,10), range(1,10));
#2
5
Or you did it this way:
或者你是这样做的:
$b = array_slice(range(0,10), 1, NULL, TRUE);
Find the output here: http://codepad.org/gx9QH7ES
在这里找到输出:http://codepad.org/gx9QH7ES
#3
1
There is no out of the box solution for this. You will have to create the array yourself, like so:
这个问题没有现成的解决方案。您必须自己创建数组,如下所示:
$temp = array();
foreach(range(1, 11) as $n) {
$temp[$n] = $n;
}
But, more importantly, why do you need this? You can just use the value itself?
但是,更重要的是,为什么你需要这个?你可以只使用值本身?
#4
0
<?php
function createArray($start, $end){
$arr = array();
foreach(range($start, $end) as $number){
$arr[$number] = $number;
}
return $arr;
}
print_r(createArray(1, 10));
?>
See output here: http://codepad.org/Z4lFSyMy
看到输出:http://codepad.org/Z4lFSyMy
#5
0
<?php
$array = array();
foreach (range(1,11) as $r)
$array[$r] = $r;
print_r($array);
?>
#6
0
Create a function to make this:
创建一个函数来实现以下目标:
if (! function_exists('sequence_equal'))
{
function sequence_equal($low, $hight, $step = 1)
{
return array_combine($range = range($low, $hight, $step), $range);
}
}
Using:
使用:
print_r(sequence_equal(1, 10, 2));
Output:
输出:
array (
1 => 1,
3 => 3,
5 => 5,
7 => 7,
9 => 9,
)
In PHP 5.5 >= you can use Generator to make this:
在PHP 5.5 >=中,您可以使用生成器来实现:
function sequence_equal($low, $hight, $step = 1)
{
for ($i = $low; $i < $hight; $i += $step) {
yield $i => $i;
}
}