试图将一个点返回到2d char数组

I'm trying to return a pointer to a 2d char array (mainly just for practice using pointers since I don't understand them too well yet).

我正在尝试返回一个指向2d char数组的指针(主要是为了练习使用指针,因为我还不太了解它们)。

When I compile this I get the message:

当我编译这个时,我收到消息:

Maze Game.cpp(32): error C2440: 'initializing' : cannot convert from 'char (*)[8]' to 'char **'

Line 32 is:

第32行是:

char** acBoard = new char[8][8];

Here is the source code:

这是源代码:

#include "stdafx.h"
#include <iostream>

char** createGrid();

int main()
{
    using namespace std;

    char** pBoard = createGrid();
    char gameBoard[8][8];

    for(int row = 0; row < 8; row++) {
        int count = 0;
        for(int col = 0; col < 8; col++) {
            char temp = **pBoard + count;
            gameBoard[row][col] = temp;
            cout << gameBoard[row][col];
        }
        cout << endl;
    }
    delete pBoard;
    pBoard = 0;

    return 0;
}





char** createGrid()
{
    char** acBoard = new char[8][8];
        //Set wall positions
    acBoard[1][6] = 'X';            
    acBoard[1][7] = 'X';
    acBoard[3][4] = 'X';
    acBoard[3][6] = 'X';
    acBoard[3][8] = 'X';
    acBoard[4][1] = 'X';
    acBoard[4][3] = 'X';
    acBoard[4][4] = 'X';
    acBoard[4][5] = 'X';
    acBoard[4][6] = 'X';
    acBoard[4][7] = 'X';
    acBoard[5][1] = 'X';
    acBoard[5][3] = 'X';
    acBoard[5][4] = 'X';
    acBoard[5][8] = 'X';
    acBoard[6][1] = 'X';
    acBoard[6][2] = 'X';
    acBoard[6][3] = 'X';
    acBoard[6][6] = 'X';
    acBoard[6][8] = 'X';
    acBoard[7][1] = 'X';
    acBoard[7][5] = 'X';
    acBoard[7][6] = 'X';
    acBoard[7][8] = 'X';
    acBoard[8][3] = 'X';
    acBoard[8][5] = 'X';
    acBoard[8][6] = 'X';
    acBoard[8][7] = 'X';
    acBoard[8][8] = 'X';

    acBoard[1][8] = 'N';
    acBoard[7][7] = 'T';
    acBoard[5][2] = 'W';
    acBoard[2][2] = '$';

    return acBoard;

}

Can anyone explain to me why this is happening?

任何人都可以向我解释为什么会这样吗?

2 个解决方案

#1

See link regards allocating a 2D array using new.

请参阅使用new分配2D数组的链接。

It's much simpler to understand if you do this:

如果你这样做,理解起来要简单得多:

struct Board
{
    char cells[8][8] ;
};

Board* create()
{
    Board* board = new Board;
    return board;
}

And of course as soon as we get that far, we realise this is C++, change struct to class and make it a proper object.

当然,只要我们到目前为止,我们就会意识到这是C ++,将struct更改为class并使其成为一个合适的对象。

#2

It's telling you exactly what the problem is - char ** and your 2D array aren't compatible types. You need:

它告诉你究竟是什么问题 - char **和你的2D阵列不兼容类型。你需要:

char (*acBoard)[8] = new char[8][8];

And corresponding changes elsewhere. Alternately, you could change your allocation to create an array of pointers to other arrays.

其他地方相应的变化。或者,您可以更改分配以创建指向其他数组的指针数组。

Aside: C++ uses 0-indexed arrays.

旁白:C ++使用0索引数组。

#1