将int转换为字符串数组

I'm looking to convert a for loop of int 1-9 to a string array, having looked around I've found some code to convert an int to a string but when I've tried to put it inside a for loop and make a string array I've been getting errors.

我正在寻找将int 1-9的for循环转换为字符串数组,看了一下我发现了一些代码将int转换为字符串但是当我试图将它放在for循环中并且make时一个字符串数组我一直在收到错误。

I've been given an assertion failure when I tried this

当我尝试这个时,我被断言失败了

#include<iostream>
#include <sstream> 
#include <string> 
using namespace std;
int main()
{
    string str[9];

    for (int a = 1; a <= 9; a++) {
        stringstream ss;
        ss << a;
        str [a] = ss.str();
        cout << str[a];
    }

    return 0;
}

And when I tried this the program kept crashing

当我尝试这个时,程序一直在崩溃

#include<iostream>
#include <sstream>  
#include <string>  
using namespace std;
int main()
{
    ostringstream str1 [9];

    for (int num = 1; num <= 9; num++) {
        str1[num]<< num;
        string geek = str1[num].str();
        cout << geek << endl;

    }

    return 0;

}

Any help would be really appreciated.

任何帮助将非常感激。

2 个解决方案

#1

c++ uses 0 based indexing. That means string str[9] supports indexes 0->8 not 1->9. In this loop:

c ++使用基于0的索引。这意味着字符串str [9]支持索引0-> 8而不是1-> 9。在这个循环中:

for (int num = 1; num <= 9; num++) {

you are attempting to index from 1->9. You should change it to this:

你试图从1-> 9索引。您应该将其更改为:

for (int num = 0; num < 9; num++) {

to loop over the whole array. Or better yet use:

遍历整个数组。或者更好地使用:

std::vector<std::string> str(9); // For dynamic storage duration 
std::array<std::string, 9> str; // For automatic storage duration
int num = 1;
for (auto& currentString : str) {
      currentStr << num++
}

#2

I think that this is the cause of the crash:

我认为这是导致崩溃的原因:

for (int num = 1; num <= 9; num++)

just change the operator to be "<9" instead of "<=9" :

只需将运算符更改为“<9”而不是“<= 9”:

for (int num = 1; num < 9; num++)

#1