如何在java中的char数组中用空格存储字符串值？

Looking this code

看这段代码

        String input="I use this method";
        String word=input.replaceAll(" ","/");
        char buf[]=word.toCharArray();

but i want to another method to doing this?

但我想要另一种方法来做到这一点?

2 个解决方案

#1

This is the easiest way I have found to convert a string including white spaces to a char array in java.

这是我发现将包含空格的字符串转换为java中的char数组的最简单方法。

String input = "I use this method";
char[] buf = input.toCharArray();

It looks like you are doing it right, but taking out all of the white space with the replaceAll(" ", "/")

看起来你做得对,但用replaceAll(“”,“/”)取出所有的空白区域

#2

From your question I'm assuming you want to save the string without truncating the whitespace in a char array.

从你的问题我假设你想保存字符串而不截断char数组中的空格。

If your remove the line " String word=input.replaceAll(" ","/"); " from your code.Then your code will work perfectly fine.PFB a sample code which might help you to understand this better

如果您从代码中删除“String word = input.replaceAll(”“,”/“);”,那么您的代码将完全正常工作.PFB示例代码可能有助于您更好地理解这一点

public static void main(String[] args) 
  {
       String input="I use this method";
       System.out.println(input.length()); //length of string before converting to char array
       //String word=input.replaceAll(" ","/");
       char buf[]=input.toCharArray();
       System.out.println(buf.length);//length of string after converting to char array
       for(int i=0;i<buf.length;i++){
       System.out.print(buf[i]); /// Print the values in char array
       }
  }

#1