I know how to use typedef in order to define a new type (label).
我知道如何使用typedef来定义新类型（标签）。
For instance, typedef unsigned char int8 means you can use "int8" to declare variables of type unsigned char.
例如，typedef unsigned char int8意味着您可以使用“int8”来声明unsigned char类型的变量。
However, I can't understand the meaning of the following statment:
但是，我无法理解以下声明的含义：
typedef unsigned char array[10]
Does that mean array is of type unsigned char[10]?
这是否意味着数组的类型是unsigned char [10]？
In other part of code, this type was used as a function argument:
在代码的其他部分，此类型用作函数参数：
int fct_foo(array* arr)
Is there anyone who is familiar with this statement?
有没有人熟悉这个陈述？
2 个解决方案
#1
29
Does that mean array is of type
unsigned char[10]?这是否意味着数组的类型是unsigned char [10]？
Replace "of" with "another name for the" and you have a 100% correct statement. A typedef introduces a new name for a type.
将“of”替换为“另一个名称”，并且您有100％正确的声明。 typedef为类型引入了新名称。
typedef unsigned char array[10];
declares array as another name for the type unsigned char[10], array of 10 unsigned char.
声明数组为unsigned char [10]类型的另一个名称，10个unsigned char数组。
int fct_foo(array* arr)
says fct_foo is a function that takes a pointer to an array of 10 unsigned char as an argument and returns an int.
fct_foo是一个函数，它将一个指向10个unsigned char数组的指针作为参数并返回一个int。
Without the typedef, that would be written as
没有typedef，那就写成了
int fct_foo(unsigned char (*arr)[10])
#2
4
What that does is it makes a datatype called array that is a fixed length array of 10 unsigned char objects in size.
它的作用是使一个名为array的数据类型是一个固定长度的数组，其大小为10个unsigned char对象。
Here is a similar SO question that was asking how to do a fixed length array and that typedef format is explained in more depth.
这是一个类似的SO问题，询问如何进行固定长度数组，并更深入地解释typedef格式。
#1
29
Does that mean array is of type
unsigned char[10]?这是否意味着数组的类型是unsigned char [10]？
Replace "of" with "another name for the" and you have a 100% correct statement. A typedef introduces a new name for a type.
将“of”替换为“另一个名称”，并且您有100％正确的声明。 typedef为类型引入了新名称。
typedef unsigned char array[10];
declares array as another name for the type unsigned char[10], array of 10 unsigned char.
声明数组为unsigned char [10]类型的另一个名称，10个unsigned char数组。
int fct_foo(array* arr)
says fct_foo is a function that takes a pointer to an array of 10 unsigned char as an argument and returns an int.
fct_foo是一个函数，它将一个指向10个unsigned char数组的指针作为参数并返回一个int。
Without the typedef, that would be written as
没有typedef，那就写成了
int fct_foo(unsigned char (*arr)[10])
#2
4
What that does is it makes a datatype called array that is a fixed length array of 10 unsigned char objects in size.
它的作用是使一个名为array的数据类型是一个固定长度的数组，其大小为10个unsigned char对象。
Here is a similar SO question that was asking how to do a fixed length array and that typedef format is explained in more depth.
这是一个类似的SO问题，询问如何进行固定长度数组，并更深入地解释typedef格式。