如何从数据库构建“子父”树/嵌套数组？

TABLE `people`
+----+------------+-------+
| sn | name       | upper |
+----+------------+-------+
|  1 | Clement    |     0 |
|  2 | Jean       |     1 |
|  3 | Annie      |     1 |
|  4 | Yuan       |     2 |
|  5 | Mei        |     2 |
|  6 | Blue       |     3 |
|  7 | Yang       |     5 |
|  8 | Lorinda    |     0 |
+----+------------+-------+

The structure is like:

结构如下：

Clement
    Jean
        Yuan
        Mei
            Yang
    Annie   
        Blue
Lorinda

The column upper states the upper person of himself/herself.

列的上部表示他/她自己的上层人物。

The problem is: How can I get a nested/multi-dimensional array from MySQL? I thought I could use loops to fetch, but I failed to automated fetch all the lowers. The array could be like this:

问题是：如何从MySQL获得嵌套/多维数组？我以为我可以使用循环来获取，但我无法自动获取所有降低。数组可能是这样的：

Array
(
    [1]=>Array
    (
        [self]=>Clement
        [2]=>Array
        (
            [self]=>Jean
            [4]=>Array
            (
                [self]=>Yuan
            )
            [5]=>Array
            (
                [self]=>Mei
                [7]=>Array
                (
                    [self]=>Yang
                )
            )
        )
        [3]=>Array
        (
            [self]=>Annie
            [6]=>Array
            (
                [self]=>Blue
            )
        )
    )
    [8]=>Array
    (
        [self]=>Lorinda
    )
)

Since we don't know how many 'upper' persons does one have, the solution should be an automated function that build a complete array, not just for three or four dimension. In other word, the function should deep into all the lower person from a top person.

由于我们不知道有多少“上层人”，因此解决方案应该是一个自动化功能，可以构建一个完整的阵列，而不仅仅是三维或四维。换句话说，该功能应该深入到*人物的所有下层人员身上。

2 个解决方案

#1

Given your input as:

鉴于您的输入为：

$input = array(
  array('sn' => 1, 'name' => 'Clement', 'upper' => 0),
  array('sn' => 2, 'name' => 'Jean',    'upper' => 1),
  array('sn' => 3, 'name' => 'Annie',   'upper' => 1),
  array('sn' => 4, 'name' => 'Yuan',    'upper' => 2),
  array('sn' => 5, 'name' => 'Mei',     'upper' => 2),
  array('sn' => 6, 'name' => 'Blue',    'upper' => 3),
  array('sn' => 7, 'name' => 'Yang',    'upper' => 5),
  array('sn' => 8, 'name' => 'Lorinda', 'upper' => 0),
);

using references you can build a tree with the following loop:

使用引用，您可以使用以下循环构建树：

$map = array();

foreach ($input as $node) {
  // init self
  if (!array_key_exists($node['sn'], $map)) {
    $map[$node['sn']] = array('self' => $node['name']);
  }
  else {
    $map[$node['sn']]['self'] = $node['name'];
  }

  // init parent
  if (!array_key_exists($node['upper'], $map)) {
    $map[$node['upper']] = array();
  }

  // add to parent
  $map[$node['upper']][$node['sn']] = & $map[$node['sn']];
}

print_r($map[0]);

demo: http://3v4l.org/vuVPu

演示：http：//3v4l.org/vuVPu

#2

Assuming the data is like this

假设数据是这样的

$data = array(
    array(1, 'Clement', 0),
    array(2, 'Jean   ', 1),
    array(3, 'Annie  ', 1),
    array(4, 'Yuan   ', 2),
    array(5, 'Mei    ', 2),
    array(6, 'Blue   ', 3),
    array(7, 'Yang   ', 5),
    array(8, 'Lorinda', 0),
);

this recursive function might work:

这个递归函数可能有效：

function tree($data, $node) {
    foreach($data as $e)
        if($e[2] == $node[0])
            $node['children'] []= tree($data, $e);
    return $node;
}

Use it like this:

像这样用它：

$tree = tree($data, array(0));
print_r($tree);

#1