使用For循环结果在Python中创建2d数组

I run some code within a for loop. I want to take the results from my loop and place them in a 2d array with 2 columns and as many rows as times I iterate the loop. Here's a simplified version of what I have:

我在for循环中运行一些代码。我想从循环中获取结果并将它们放在一个2列数组中，其中包含2列和多次行迭代循环。这是我的简化版本：

 for i in range(10):

      'bunch of stuff'

      centerx = xc
      centery = yc

How can I save my values for centerx and centery in a 2d array with 2 columns and 10 rows? Any help is appreciated, thanks!

如何在具有2列和10行的2d数组中保存centerx和centery的值？任何帮助表示赞赏，谢谢！

3 个解决方案

#1

You can try this:

你可以试试这个：

import numpy as np
listvals = []
for i in range(10):
    listvals.append((xc, yc))
mat_vals = np.vstack(listvals)

This will output an ndarray like this:

这将输出如下的ndarray：

[[ 2  0]
 [ 3  1]
 [ 4  2]
 [ 5  3]
 [ 6  4]
 [ 7  5]
 [ 8  6]
 [ 9  7]
 [10  8]
 [11  9]]

Or this maybe is better:

或者这可能更好：

import numpy as np
list_xc = []
list_yc = []
for i in np.arange(10): 
    list_xc.append(xc)
    list_yc.append(yc)
mat_xc = np.asarray(list_xc)
mat_yc = np.asarray(list_yc)
mat_f = np.column_stack((mat_xc, mat_yc))

#2

You can do this:

你可以这样做：

aList = []
for i in range(10):
    aList.append([xc, yc])

#3

Try this comprehension,

尝试这种理解，

[ [i, i*10] for i in range(5) ]

which delivers

提供

[[0, 0], [1, 10], [2, 20], [3, 30], [4, 40], [5, 50]]

#1