使用AJAX将变量javascript传递给PHP

I am trying to pass a single variable from javascript to PHP using jQuery AJAX.

我试图使用jQuery AJAX将单个变量从javascript传递给PHP。

Javascript:

使用Javascript：

$(document).ready(function() {
    $('.ok').on('click', function(e){

        var value = 5;

        $.ajax({
            url: 'tabulka.php',
            type: "POST",
            data: {x : value},
            success: function(){
                alert(value);
            }
        });
    });
});

PHP:

PHP：

if($_SERVER['REQUEST_METHOD']){
    $value = $_POST['x'];
    echo $value;
}

I get the alert from ajax with the expected value but in PHP I get this error: Notice: Undefined index: value in C:\xampp\htdocs\test\tabulka.php on line 71 When I uncomment the dataType: 'json' I don't even get the alert from AJAX.

我从ajax获得了具有预期值的警报但在PHP中我收到此错误：注意：未定义的索引：第71行的C：\ xampp \ htdocs \ test \ tabulka.php中的值当我取消注释dataType时：'json'I甚至没有从AJAX获得警报。

3 个解决方案

#1

Instead of this

而不是这个

data: ({value : value}),

Try using this,

试试这个，

 data: "value="+value,

And you are not at all passing "OK" but you are receiving it. If you want to pass OK also as a parameter try this.

你并没有完全“好”，但是你正在接受它。如果你想传递OK作为参数试试这个。

data: "value="+value+"&OK=Somevalue",

That should work.

这应该工作。

#2

Your JavaScript

你的JavaScript

data: {'value' : value}

notice the single quote and no parenthesis

注意单引号而没有括号

Your PHP:

你的PHP：

If(isset($_POST['value'])){
   $val = $_POST['value'];
}

Your JavaScript was formatted incorrectly. data is an object, or an associative array in other words.

您的JavaScript格式不正确。数据是一个对象，换句话说就是一个关联数组。

Your PHP code has unnecessary string comparison. Whenever a post is made to a PHP script, you will access them using $_POST array.

您的PHP代码有不必要的字符串比较。每当发布一个PHP脚本的帖子时，您将使用$ _POST数组访问它们。

For instance, if you posted this via AJAX

例如，如果您通过AJAX发布此内容

data:{ 'name' : 'jake', 'age' : 1024}

You would access them in PHP by

你可以在PHP中访问它们

  $name = $_POST['name']
    $age = $_POST['age']

Also, it is wise to use PHP isset to verify that a post variable exists before trying to access them. That way you will not have an exception if expected post data is not.

此外，在尝试访问它们之前，最好使用PHP isset验证post变量是否存在。这样，如果没有预期的后期数据，您就不会有例外。

#3

check following line

检查以下行

var value = $(this).find('td:first').html();

set some hard coded value for 'value' variable like below

为'value'变量设置一些硬编码值，如下所示

var value='some value';

if above works then check the value you assigned using $(this).find('td:first').html()

如果以上工作，然后使用$（this）.find（'td：first'）检查您分配的值.html（）

#1