将JavaScript数组从视图传递给Laravel控制器

I am trying to pass objs array to a function in Laravel controller using ajax. I am not recieving any data after the post.

我正在尝试使用ajax将objs数组传递给Laravel控制器中的函数。我没有收到任何事后的数据。

<script>

        var itemCount = 0;
        var objs=[];
        $(document).ready(function(){


            var temp_objs=[];

            $( "#add_button" ).click(function() {

                var html = "";

                var obj = {
                    "ROW_ID": itemCount,
                    "STREET_ADDRESS": $("#street_address").val(),
                    "CITY": $("#city").val(),
                    "ZIP": $("#zip").val()
                }

                // add object
                objs.push(JSON.stringify(obj));

                itemCount++;
                // dynamically create rows in the table
                html = "<tr id='tr" + itemCount + "'><td>" + obj['STREET_ADDRESS'] + "</td> <td>" + obj['CITY'] + " </td> <td>" + obj['ZIP'] + " </td><td><input type='button'  id='" + itemCount + "' value='remove'></td> </tr>";

                //add to the table
                $("#multiple_table").append(html)

                // The remove button click
                $("#" + itemCount).click(function () {
                    var buttonId = $(this).attr("id");
                    //write the logic for removing from the array
                    $("#tr" + buttonId).remove();
                });

            });

            $("#submit").click(function() {
                $.ajax({
                    url:'/app/Http/Controllers/Search/search_address',
                    type: 'POST',
                    dataType:'json',
                    contentType: 'application/json',

                    data: objs
                });

            });

        });



    </script>

In my controller function is like this

我的控制器函数是这样的

public function search_address(){
    $data = json_decode($_POST['data'], true);
    print_r($data);
}

I guess that I am having a problem with the url in ajax and I am not sure how a controller's url is obtained.

我想我对ajax中的url有问题，我不确定如何获得控制器的url。

Thank you

谢谢你！

2 个解决方案

#1

Can you change:

你能改变:

$data = json_decode($_POST['data'], true);

to:

$data = json_decode(Input::get('data'));

and make sure you have: use Input; above your class extends Controller

确保你有:使用输入;在类之上扩展控制器

See if that works.

看看这个行不行。

Edit: Also make sure your routes (in the Controllers folder) are correct.

编辑:还要确保您的路由(在controller文件夹中)是正确的。

#2

You should console.log() your javascript by placing the following in you ajax post:

您应该在ajax post中放置以下内容来协调.log() javascript:

error : function(e){
   console.log(e);
}

You can then see what errors you are getting in your browsers' developers tools panel.

然后可以看到浏览器的开发人员工具面板中出现了什么错误。

You should also be aware that that Laravel posts require a csrf token unless you have explicitly turned them off, which means you will need to add this token in to your post as well. So you should end up with:

您还应该注意，Laravel的帖子需要一个csrf令牌，除非您已经显式地关闭它们，这意味着您也需要将这个令牌添加到您的帖子中。所以你应该这样结束:

$("#submit").on('click', function() {
    $.ajax({
        url:'/app/Http/Controllers/Search/search_address', // Is this what you meant, is this the route you set up?
        type: 'POST',
        data: {'data': objs, '_token' : '<?=csrf_token()?>'},
        success : function(data){
          // Do what you want with your data on success
        },
        error : function(e){
           console.log(e);
        }
    });
});

Notice that I've embedded php inside the javascript, which is just to illustrate the point. Ideally javascript is kept in it's own files, so you would then need to find a way to pass this token through. I personally use knockoutjs for this type of thing (AngularJS is also popular), but you can easily do something like:

注意，我在javascript中嵌入了php，这只是为了说明这一点。理想情况下，javascript被保存在它自己的文件中，因此您需要找到一种方法来传递这个令牌。我个人使用knockoutjs来处理这类事情(AngularJS也很受欢迎)，但是你可以轻松地完成以下事情:

<input type="hidden" id="_token" value="{{ csrf_token() }}" />

in your HTML, then pull this value from inside your ajax request:

在HTML中，然后从ajax请求中提取这个值:

data: {'data': objs, '_token' : $('#_token').val()}

EDIT

编辑

I've just noticed your url, it looks like you are trying to access the controller directly. You need to set up a route in your routes.php file, such as:

我刚注意到你的url，看起来你想直接访问控制器。你需要在你的路线上建立一条路线。php文件,例如:

Route::post('/searchAddress', 'YourController@search_address');

Then use:

然后使用:

url: /searchAddress

in your ajax request.

在您的ajax请求。

#1