基于键从多维数组中删除元素

How can I delete an element from a multi-dimensional array given a key?

如何在给定键的情况下从多维数组中删除元素？

I am hoping for this to be greedy so that it deletes all elements in an array that match the keys I pass in. I have this so far where I can traverse a multi-dimensional array but I can't unset the key I need to because I don't have a reference to it!

我希望这是贪婪的，这样它就会删除数组中与我传入的键相匹配的所有元素。到目前为止，我已经可以遍历多维数组，但是我无法取消我需要的键。因为我没有参考它！

function traverseArray($array, $keys)
{ 
    foreach($array as $key=>$value)
    { 
        if(is_array($value))
        { 
            traverseArray($value); 

        } else {

            if(in_array($key, $keys))
           {                    
                //unset(what goes here?) 

            }

        } 
    }

}

4 个解决方案

#1

The following code works (and doesn't use deprecated stuff), just tested it:

以下代码有效（并且不使用已弃用的东西），只是测试了它：

function traverseArray(&$array, $keys) { 
  foreach ($array as $key => &$value) { 
    if (is_array($value)) { 
      traverseArray($value, $keys); 
    } else {
      if (in_array($key, $keys)){
        unset($array[$key]);
      }
    } 
  }
}

#2

You could use pass by reference, declare your function like this:

你可以使用pass by reference，声明你的函数如下：

function traverseArray(&$array, $keys)
{ 
    foreach($array as $key=>$value)
    { 
        if(is_array($value))
        { 
            traverseArray($value, $keys); 
        }else{
            if(in_array($key, $keys)){
                unset($array[$key]);
            }
        } 
    }
}

then you can unset the key and it will vanish from the original passed value too since the $array in the function is merely a pointer to the array you passed so it updates that array.

那么你可以取消设置密钥，它也将从原始传递的值中消失，因为函数中的$数组只是指向你传递的数组的指针，因此它更新了该数组。

unset($array[$key]);

For more information check the php documentation on passing by reference

有关更多信息，请查看有关通过引用传递的php文档

#3

You can do this

你可以这样做

unset($array[$key]);

because $array will not be a copy of the original array, just a reference to it, so any modifications will hold.

因为$ array不是原始数组的副本，只是对它的引用，所以任何修改都会成立。

Also, you have a small bug in your snippet: when you make the recursive call, you forget the pass the $keys parameter.

此外，您的代码段中有一个小错误：当您进行递归调用时，您忘记了传递$ keys参数。

#4

and don't forget to modify foreach:

并且不要忘记修改foreach：

foreach($array as $key=>&$value)

#1