从javascript数组中拼接2个键的最佳方式

I have the following Object:

我有以下目标:

var obj = { "2014": {}, "2013": {}, "2012": {}, "description": null, "image": null },
    objKeys = Object.keys(obj);
//objKeys contains [ "2014", "2013", "2012", "description", "image" ]

I would like to remove the "description" and "image" from the objKeys array in one go if they exists there.

如果objKeys数组中存在“description”和“image”，我想一次性删除它们。

How can I achieve that ?

我怎么才能做到呢?

4 个解决方案

#1

You can filter them out like this:

你可以这样过滤它们:

objKeys = objKeys.filter(function(x){ return !/[a-z]/gi.test(x)});

The above uses the fact that other keys are numbers. If you want only description and image, then put them in an array and do this:

上面使用的事实是其他键都是数字。如果你只需要描述和图像，然后把它们放在一个数组中，然后这样做:

var removeKeys = ["description","image"];
objKeys = objKeys.filter(function(x){ return !new RegExp(removeKeys.join("|")).test(x)});

#2

Are the keys you wish to keep always numeric? I'm assuming they're "years"...

您希望始终保持数字键吗?我假设他们“年”…

objKeys.filter(Number); // ["2012", "2013", "2014"]

#3

You can filter them directly using regex.

您可以使用regex直接过滤它们。

objKeys = objKeys.filter(function(k){ return !/(description|image)/gi.test(k)});

#4

A small modification to @hutchbat's answer, why two iterations over keys?

对@hutchbat的回答进行了小小的修改，为什么要对键进行两次迭代?

Object.keys is one and filter is another. Here is my code

对象。键是一个，过滤器是另一个。这是我的代码

var objKeys = [];
for(var i in obj) if(!/(description|image)/gi.test(i)) objKeys.push(i);

So it iterates one times and collects required.

它迭代1次并收集所需的数据。

#1