从数组按值拼接行

时间:2021-11-07 21:28:41

I want splice the line with value = 3

我要将值= 3的线拼接起来

[3,"John", 90909090]

data.json

data.json

{
"headers":[[
{"text":"Code","class":"Code"},
{"text":"Code","class":"Code"}
]],
"rows":[
[0,"Peter", 51123123],
[3,"John", 90909090],
[5,"Mary",51123123]
],
"config":[[0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]],
"other":[[13,0]]
}

I try this:

我试试这个:

var size = data.rows.length; // number of rows

var del = 3 // Value of ID to be deleted          

for (i = 0; i < size; i++) {  

var id = data.rows[i][0];                  

    if(del==id){  // if del = id -> splice                                         

       data.rows.splice(i,1);

    }

}

Results:

结果:

Only splice or only loop this code works.

只有splice或仅循环此代码工作。

But, with both show this error:

但是,两者都显示了这个错误:

Uncaught TypeError: Cannot read property '0' of undefined(…)

未捕获类型错误:无法读取未定义(…)的属性'0'

It occurs in "data.rows[i][0]"

它发生在“data.rows[我][0]”

4 个解决方案

#1


1  

You can iterate with Array#forEach():

可以使用数组#forEach()进行迭代:

var data = {"headers": [[{"text": "Code","class": "Code"}, {"text": "Code","class": "Code"}]],"rows": [[0, "Peter", 51123123],[3, "John", 90909090],[5, "Mary", 51123123]],"config": [[0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],"other": [[13, 0]]},
    del = 3; // Value of ID to be deleted

data.rows.forEach(function(item, index) {
  item[0] === del && data.rows.splice(index, 1);
});

console.log(data.rows);
.as-console-wrapper { max-height: 100% !important; top: 0; }

ES6:

ES6:

data.rows.forEach((item, index) => item[0] === del && data.rows.splice(index, 1));

#2


3  

instead of using a for loop, id use the array filter function:

id不使用for循环,而是使用数组过滤器函数:

data.rows = data.rows.filter(function(row){
    return row[0] !== del;
});

#3


2  

Just add a break to the condition, because the next element, is the one you have spliced, which is not anymore in the array.

只需要在条件中添加一个断点,因为下一个元素,是你已经拼接过的,它不在数组中了。

if (del == id) {  // if del = id -> splice
   data.rows.splice(i, 1);
   break; // no more to search
}

#4


0  

You can use lodash for filter your objects or arrays. Look at the filter method for your case:

可以使用lodash来过滤对象或数组。请查看您的案例的筛选方法:

var myObject = {
"headers":[[
{"text":"Code","class":"Code"},
{"text":"Code","class":"Code"}
]],
"rows":[
[0,"Peter", 51123123],
[3,"John", 90909090],
[5,"Mary",51123123]
],
"config":[[0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]],
"other":[[13,0]]
};

//filter by lodash
myObject.rows =  _.filter(myObject.rows,function(row){
  return row[0] !== 3;
});

#1


1  

You can iterate with Array#forEach():

可以使用数组#forEach()进行迭代:

var data = {"headers": [[{"text": "Code","class": "Code"}, {"text": "Code","class": "Code"}]],"rows": [[0, "Peter", 51123123],[3, "John", 90909090],[5, "Mary", 51123123]],"config": [[0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]],"other": [[13, 0]]},
    del = 3; // Value of ID to be deleted

data.rows.forEach(function(item, index) {
  item[0] === del && data.rows.splice(index, 1);
});

console.log(data.rows);
.as-console-wrapper { max-height: 100% !important; top: 0; }

ES6:

ES6:

data.rows.forEach((item, index) => item[0] === del && data.rows.splice(index, 1));

#2


3  

instead of using a for loop, id use the array filter function:

id不使用for循环,而是使用数组过滤器函数:

data.rows = data.rows.filter(function(row){
    return row[0] !== del;
});

#3


2  

Just add a break to the condition, because the next element, is the one you have spliced, which is not anymore in the array.

只需要在条件中添加一个断点,因为下一个元素,是你已经拼接过的,它不在数组中了。

if (del == id) {  // if del = id -> splice
   data.rows.splice(i, 1);
   break; // no more to search
}

#4


0  

You can use lodash for filter your objects or arrays. Look at the filter method for your case:

可以使用lodash来过滤对象或数组。请查看您的案例的筛选方法:

var myObject = {
"headers":[[
{"text":"Code","class":"Code"},
{"text":"Code","class":"Code"}
]],
"rows":[
[0,"Peter", 51123123],
[3,"John", 90909090],
[5,"Mary",51123123]
],
"config":[[0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]],
"other":[[13,0]]
};

//filter by lodash
myObject.rows =  _.filter(myObject.rows,function(row){
  return row[0] !== 3;
});