ValueError: x和y必须具有相同的第一个维度ipython 3.5。

I am new to ipython. I have this snippet of code in my ipython

我是ipython的新成员。我在ipython中有这段代码。

def derivative(x):
    return 3*(x^2)
derivative_estimate = lambda x: difference_quotient(cube, x, h=0.00001)

x = range(-10, 10)
import matplotlib.pyplot as plt
plt.title("Actual Derivatives vs Estimates")
x = range(-10,10)
plt.plot(x, map(derivative, x), 'rx', label = 'Actual')           # red  x
plt.plot(x, map(derivative_estimate, x), 'b+', label = 'Estimate')  # blue +
plt.show()

When I try to run this, it shows me these errors

当我试图运行它时，它显示了这些错误。

ValueError                                Traceback (most recent call last)
<ipython-input-12-211954bb4dc5> in <module>()
      6 plt.title("Actual Derivatives vs Estimates")
      7 x = range(-10,10)
----> 8 plt.plot(x, map(derivative, x), 'rx')           # red  x
      9 plt.plot(x, map(derivative_estimate, x), 'b+')  # blue +
     10 plt.show()

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\pyplot.py in plot(*args, **kwargs)
   3152         ax.hold(hold)
   3153     try:
-> 3154         ret = ax.plot(*args, **kwargs)
   3155     finally:
   3156         ax.hold(washold)

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\__init__.py in inner(ax, *args, **kwargs)
   1809                     warnings.warn(msg % (label_namer, func.__name__),
   1810                                   RuntimeWarning, stacklevel=2)
-> 1811             return func(ax, *args, **kwargs)
   1812         pre_doc = inner.__doc__
   1813         if pre_doc is None:

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\axes\_axes.py in plot(self, *args, **kwargs)
   1422             kwargs['color'] = c
   1423 
-> 1424         for line in self._get_lines(*args, **kwargs):
   1425             self.add_line(line)
   1426             lines.append(line)

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\axes\_base.py in _grab_next_args(self, *args, **kwargs)
    384                 return
    385             if len(remaining) <= 3:
--> 386                 for seg in self._plot_args(remaining, kwargs):
    387                     yield seg
    388                 return

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\axes\_base.py in _plot_args(self, tup, kwargs)
    362             x, y = index_of(tup[-1])
    363 
--> 364         x, y = self._xy_from_xy(x, y)
    365 
    366         if self.command == 'plot':

C:\Users\User\Anaconda3\lib\site-packages\matplotlib\axes\_base.py in _xy_from_xy(self, x, y)
    221         y = _check_1d(y)
    222         if x.shape[0] != y.shape[0]:
--> 223             raise ValueError("x and y must have same first dimension")
    224         if x.ndim > 2 or y.ndim > 2:
    225             raise ValueError("x and y can be no greater than 2-D")

ValueError: x and y must have same first dimension,

Can anyone please help me to solve this issue?

有人能帮我解决这个问题吗?

2 个解决方案

#1

Matplotlib's plot function can't handle the iterator returned by map. Expand the iterator to a list before calling plot:

Matplotlib的plot函数不能处理映射返回的迭代器。在调用plot之前将迭代器扩展到列表:

plt.plot(x, list(map(derivative, x)), 'rx', label = 'Actual')

#2

Try to import numpy and then use either numpy.linspace or numpy.arange instead of range. I believe your problem is created inside your function derivative, where you take 3*x. If x is a list (which is returned from the standard range, 3*x will return [1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4] if x=[1, 2, 3, 4]. What you want to get is 3*x = [3, 6, 9, 12], and this will be the case if you use numpy.linspace or numpy.arange instead.

尝试导入numpy，然后使用numpy。linspace或numpy。而不是范围不等。我相信你的问题是在你的函数导数中产生的，你取3*x。如果x是一个列表(从标准范围返回，3*x将返回[1、2、3、4、1、2、3、4、1、2、3、4]，如果x=[1、2、3、4]。你想得到的是3*x =[3, 6, 9, 12]，如果你用的是numpy，情况就是这样。linspace或numpy。而不等。

Documentation links: numpy.arange and numpy.linspace

文档链接:numpy。论坛和numpy.linspace

#1