如何在R中创建列表矩阵？

What i want to have is a matrix in which each element is a list itself. See the following example:

我想要的是一个矩阵，其中每个元素本身就是一个列表。请参阅以下示例：

1       2       3
1  1,2,4  1,2      1
2  Null   3,4,5,6  1,3

I saw this post, and tried the following but got an error :

我看到这篇文章，并尝试了以下但有一个错误：

 b <- array()
 b[j, i, ] <- A[i]

where A is a vector itself. The error was:

其中A是矢量本身。错误是：

 Error in b[j, i, ] <- A[i] : incorrect number of subscripts

How should I define and access each element of the matrix and each element of the contained lists?

我应该如何定义和访问矩阵的每个元素以及所包含列表的每个元素？

Update1 :

Update1：

b<-matrix(list(),nrow = length(d), ncol =length(c))

Error in b[j, i] <- A[i] : replacement has length zero

I want to specify that each element is a list and then try to fill it with various list with different length from zero to n.

我想指定每个元素是一个列表，然后尝试用从0到n的不同长度的各种列表填充它。

Update2 :

Update2：

 running what @BondedDust commented :
 b<-matrix(rep(list(),(c*d)),,nrow = length(d), ncol =length(c))
 Erorr in b[[j*nrow(b)+i]] <- A[i] : attempt to select less than one element

A :

A ：

A[1]<-c(3)     F[[1]]<-numeric(0)   E[[1]]<-numeric(0)
A[2]<-c(1)     F[2]<-c(1)           E[2]<-c(1)
A[3]<-c(1)     F[3]<-c(2)           E[[3]]<-numeric(0)
A[[4]]<-c(1,3) F[[4]]<-numeric(0)   E[[4]]<-numeric(0)
A[5]<-c(4)     F[5]<-c(4)           E[5]<-c(4)

A :values of row 1 , F:row 2 and E :row 3. ( 5 column )

A：第1行的值，F：第2行和第3行：第3行（第5列）

this data is not in this form and is not stored any where,they are the output of another function (there is function in the place of A[i]).the data just show what dose A look likes reproducibly and therefore shows the position in the matrix and gives back the error in update2.A[4] is the element of column 4 row 2.

这个数据不是这种形式，也不是存储在任何地方，它们是另一个功能的输出（在A [i]的位置有功能）。数据只显示A看起来像重复的剂量，因此显示位置在矩阵中并返回update2.A [4]中的错误是第4列第2行的元素。

1 个解决方案

#1

This builds that matrix although the print method does not display it in the manner you imagined:

这会构建该矩阵，尽管print方法不会以您想象的方式显示它：

 matrix( list(c(1,2,4), c(NULL), c(1,2), c(3,4,5,6), c(1), c(1,3)), 2,3)
 #---------
     [,1]      [,2]      [,3]     
[1,] Numeric,3 Numeric,2 1        
[2,] NULL      Numeric,4 Numeric,2

Inspect the first element:

检查第一个元素：

> Mlist <- matrix( list(c(1,2,4), c(NULL), c(1,2), c(3,4,5,6), c(1), c(1,3)), 2,3)
> Mlist[1,1]
[[1]]
[1] 1 2 4

> is.matrix(Mlist)
[1] TRUE
> class( Mlist[1,1] )
[1] "list"

Demonstration of creating "matrix of lists" from a list:

从列表中创建“列表矩阵”的演示：

> will.become.a.matrix <- list(c(1,2,4), c(NULL), c(1,2), c(3,4,5,6), c(1), c(1,3))
> is.matrix(will.become.a.matrix)
[1] FALSE
> dim(will.become.a.matrix) <- c(2,3)
> is.matrix(will.become.a.matrix)
[1] TRUE
> dim(will.become.a.matrix)
[1] 2 3
> class(will.become.a.matrix[1,1])
[1] "list"

Further requested demonstration:

进一步要求示范：

 A<- list(); F=list() E=list()
 A[1]<-c(3) ;  F[[1]]<-numeric(0);  E[[1]]<-numeric(0)
 A[2]<-c(1) ;  F[2]<-c(1)   ;        E[2]<-c(1)
 A[3]<-c(1) ;  F[3]<-c(2)  ;         E[[3]]<-numeric(0)
 A[[4]]<-list(1,3) ;F[[4]]<-numeric(0) ; E[[4]]<-numeric(0)
 A[5]<-c(4) ; F[5]<-c(4)       ;    E[5]<-c(4)
 Mlist= c(A,F,E)
 M <- matrix(Mlist, length(A), 3)
#=====================================
> M
     [,1]   [,2]      [,3]     
[1,] 3      Numeric,0 Numeric,0
[2,] 1      1         1        
[3,] 1      2         Numeric,0
[4,] List,2 Numeric,0 Numeric,0
[5,] 4      4         4

You asked (in comments) "....is there a way to define number of column and rows , but not the element itself because they are unknown?"

你问（在评论中）“....有没有办法定义列和行的数量，但不是元素本身，因为它们是未知的？”

Answered (initially in comments)

回答（最初在评论中）

b<-matrix(rep(list(), 6),nrow = 2, ncol =3) 
#.... then replace the NULL items with values. 
# Need to use "[[": for assignment (which your 'Update 1' did not 
# ....and your Update2 only did for some but not all of the assignments.)

b[[1]] <- c(1,2,3,4)

#1