相信DropDownList 控件不能触发SelectedIndexChanged 事件已经不是什么新鲜事情了,原因也无外乎以下几种:
1、DropDownList 控件的属性 AutoPostBack="True" 没有写;
2、DropDownList 控件的数据绑定没有放在if (!Page.IsPostBack) 里面;
3、DropDownList 控件选定项的value 值只有在发生变化时,才将信息发往服务器;
有人问
(1)AutoPostBack="True"
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<asp:DropDownList id="DropDownList1" runat="server" AutoPostBack="True"></asp:DropDownList>
(2)事件也注册了
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this.DropDownList1.SelectedIndexChanged += new System.EventHandler(this.DropDownList1_SelectedIndexChanged);
(3)事件也写了
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private void DropDownList1_SelectedIndexChanged(object sender, System.EventArgs e)
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{
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Response.Write(this.DropDownList1.SelectedItem);
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}
怎么还是不能输出选定项?进行调试发现不能进入SelectedIndexChanged事件。
其实还有一种可能,就是你为DropDownList的不同option设置了相同的value
比如后台这么写:
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if(!IsPostBack)
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{
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for(int i=0;i<10;i++)this.DropDownList1.Items.Add(new ListItem(i.ToString(),"same_value"));
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}
这样不会触发SelectedIndexChanged事件,修改成
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if(!IsPostBack)
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{
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for(int i=0;i<10;i++)this.DropDownList1.Items.Add(new ListItem(i.ToString(),i.ToString()));
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}
一切些正常,根据msdn的解释:
ListControl.SelectedIndexChanged 事件
当列表控件的选定项在信息发往服务器之间变化时发生
这不同于js的onchange事件,改为
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if(!IsPostBack)
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{
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for(int i=0;i<10;i++)this.DropDownList1.Items.Add(new ListItem(i.ToString(),"same_value"));
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this.DropDownList1.Attributes.Add("onchange","alert('test');");
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}
测试可知。