I have a matrix called data. It contains 3 columns, company name, company value & company currency, bit like below.
我有一个矩阵叫做数据。它包含3列,公司名称,公司价值和公司货币,如下所示。
Name Value Currency
ABC 10 USD
MNO 5 JPY
PLM 3 USD
NJK 7 EUR
I need to sum the total value for each currency so my answer would look like below,
我需要对每种货币的总价值进行求和,所以我的答案应该是这样的,
Currency Value
EUR 7
JPY 5
USD 13
I know I can do this using a loop but is it possible using an anonymous function and if so how?
我知道我可以用一个循环来做,但是用一个匿名函数可以吗?
Update - Extra information as original post lacked information
更新-额外的信息,因为原始的帖子缺少信息
Below is my solution, which works. However I have seen people use cellFun or anonymous functions and fell like there is a more efficient way (and would to like alternative way) for problems of this nature
下面是我的解决方案,它是有效的。然而,我看到人们使用cellFun或匿名函数,并认为有一种更有效的方法(也希望有另一种方法)来解决这类问题
val = cell2mat(data(:, 2)); % double - value
sedols = data(:, [1 3]); % cell - name (1st column) and currency (2nd column)
ccy = unique(sedols(:, 2));
fx_exp = zeros(length(ccy(:, 1)), 1);
for n = 1 : length(ccy(:, 1))
index = strmatch(ccy(n, 1), sedols(:, 2));
fx_exp(n, 1) = sum(val(index));
end
1 个解决方案
#1
5
Using cellfun
or arrayfun
is not more efficient than a simple loop. To take advantage of vectorization you need to work with pure double arrays.
使用cellfun或arrayfun并不比简单的循环更有效。为了利用矢量化,您需要使用纯双数组。
Assuming your data is stored in a cell array, unique
combined with accumarray
is the way to go:
假设您的数据存储在一个单元数组中,那么与accumarray结合使用是唯一的:
data = {
'ABC' 10 'USD'
'MNO' 5 'JPY'
'PLM' 3 'USD'
'NJK' 7 'EUR' };
[a,b,subs] = unique(data(:,3))
vals = [data{:,2}];
currsum = accumarray(subs,vals)
out = [data(b,3) num2cell(currsum)]
out =
'EUR' [ 7]
'JPY' [ 5]
'USD' [13]
#1
5
Using cellfun
or arrayfun
is not more efficient than a simple loop. To take advantage of vectorization you need to work with pure double arrays.
使用cellfun或arrayfun并不比简单的循环更有效。为了利用矢量化,您需要使用纯双数组。
Assuming your data is stored in a cell array, unique
combined with accumarray
is the way to go:
假设您的数据存储在一个单元数组中,那么与accumarray结合使用是唯一的:
data = {
'ABC' 10 'USD'
'MNO' 5 'JPY'
'PLM' 3 'USD'
'NJK' 7 'EUR' };
[a,b,subs] = unique(data(:,3))
vals = [data{:,2}];
currsum = accumarray(subs,vals)
out = [data(b,3) num2cell(currsum)]
out =
'EUR' [ 7]
'JPY' [ 5]
'USD' [13]