laravel 4：如何在更新行时从列的当前值中减去一个？

I was wondering how to perform something like this:

我想知道如何执行这样的事情:

Table::update(array('position'=>'position+1'));

As far as I know, laravel 4 handles 'position+1' as a string, thus is becomes 0.

据我所知,laravel 4将'position + 1'作为一个字符串处理,因此变为0。

I want to perform something like

我想表现得像

UPDATE table SET position = position + 1

Can I do that using eloquent?

我能用口才吗?

EDIT: nevermind, doh.."DB::table('users')->increment('votes');"

编辑:没关系,doh ..“DB :: table('users') - > increment('votes');”

4 个解决方案

#1

Simply make use of the increment method:

只需使用增量方法:

DB::table('users')->increment('position');

The same is valid for decrement:

同样适用于减量:

DB::table('users')->decrement('rank');

You may even set the second parameter to the amount you want to add/subtract:

您甚至可以将第二个参数设置为要添加/减去的数量:

DB::table('users')->increment('posts', 5);
DB::table('users')->decrement('likes', 3);

Also, if you need to update other columns along with it, you pass it as the third parameter:

此外,如果您需要更新其他列,请将其作为第三个参数传递:

DB::table('users')->increment('range', 3, array(
    'name' => 'Raphael',
    'rank' => 10
));

And the same goes for Eloquent models, as well:

对于Eloquent模型也是如此:

$firstUser = User::find(1);
$firstUser->increment('height', 0.1, array(
    'active' => false
));

#2

you can also do with DB::raw method like this:

您也可以使用DB :: raw方法,如下所示:

DB::table('tablename')->where(your condition)->update(['position' => DB::raw('position+1')]);

you can also do other operations with this like

你也可以用这个做其他操作

DB::table('tablename')->where(your condition)->update(['position' => DB::raw('position * 2')]);

#3

This worked fine for me

这对我来说很好

\Models\User::where("id", $userId)->increment("points");

#4

-1

simply you can use the DB::raw method like this： Table::update(DB::raw('position=position+1'));

你可以使用像这样的DB :: raw方法:Table :: update(DB :: raw('position = position + 1'));

#1