import numpy as np
a = np.array([1,2,3,4,5,6,7,8,9])
b = np.where (a==3,np.nan,a)
print (b) #OK, can convert certain values (e.g. 3) into np.nan
c = np.where (b==np.nan,3,b)
print (c)
But does not work! Could not convert np.nan into 3. How can I convert np.nan in the array c into the value 3? The result (array c) should be same as the original array a.
但是不起作用！无法将np.nan转换为3.如何将数组c中的np.nan转换为值3？结果（数组c）应与原始数组a相同。
2 个解决方案
#1
5
c = np.where(np.isnan(b), 3, b)
#2
3
Working with nan is a little tricky because nan != nan. You could use np.isnan and boolean indexing, though:
使用nan有点棘手，因为nan！= nan。您可以使用np.isnan和布尔索引，但是：
>>> a = np.arange(10.0)
>>> a
array([ 0., 1., 2., 3., 4., 5., 6., 7., 8., 9.])
>>> a[a % 3 == 0] = np.nan
>>> a
array([ nan, 1., 2., nan, 4., 5., nan, 7., 8., nan])
>>> a[np.isnan(a)] = 999
>>> a
array([ 999., 1., 2., 999., 4., 5., 999., 7., 8., 999.])
#1
5
c = np.where(np.isnan(b), 3, b)
#2
3
Working with nan is a little tricky because nan != nan. You could use np.isnan and boolean indexing, though:
使用nan有点棘手，因为nan！= nan。您可以使用np.isnan和布尔索引，但是：
>>> a = np.arange(10.0)
>>> a
array([ 0., 1., 2., 3., 4., 5., 6., 7., 8., 9.])
>>> a[a % 3 == 0] = np.nan
>>> a
array([ nan, 1., 2., nan, 4., 5., nan, 7., 8., nan])
>>> a[np.isnan(a)] = 999
>>> a
array([ 999., 1., 2., 999., 4., 5., 999., 7., 8., 999.])