错误：在非结构或联合的事物中请求成员'数据'

I'm trying to practice Binnary trees. I created a struct for node, allocated it for the root and also allocated space for the left son. I built a function that returnes the size of the tree but it seems there is an error while trying to initialize the left son's variables.

我正在尝试练习Binnary树。我为节点创建了一个结构，为根分配了它，并为左子分配了空间。我构建了一个返回树大小的函数，但是在尝试初始化左子变量时似乎存在错误。

the main function:

主要功能：

int main()
{
node* root = (node*) malloc(sizeof(node));//allocate space for root
root->data = 7;
root->left = (node*) malloc(sizeof(node));//allocate space for left son of root
root->right = NULL;

root->left.data = 8;//ERROR HERE!
root->left.left = NULL;//ERROR HERE!
root->left.right = NULL;//ERROR HERE!


printf("size of tree: %d\n", sizeOfTree(root));
return 0;
}

the node struct:

节点结构：

typedef struct
{
int data;
struct node* left;
struct node* right;
}node;

The Errors i get:

我得到的错误：

error: request for member 'data' in something not a structure or union|
error: request for member 'left' in something not a structure or union|
error: request for member 'right' in something not a structure or union|

What am i doing wrong?

我究竟做错了什么？

1 个解决方案

#1

You got error there because you try to access that pointer with . instead of ->. Also typedef struct should be typedef struct node.

你有错误，因为你试图访问该指针。而不是 - >。 typedef struct也应该是typedef struct node。

Try this:

尝试这个：

#include<stdio.h>
#include<stdlib.h>

typedef struct node{
    int data;
    struct node* left;
    struct node* right;
}node;


int main(void){
    node* root = malloc(sizeof(node));//allocate space for root
    root->data = 7;
    root->left = malloc(sizeof(node));//allocate space for left son of root
    root->right = NULL;

    root->left->data = 8;//ERROR HERE!
    root->left->left = NULL;//ERROR HERE!
    root->left->right = NULL;//ERROR HERE!


    printf("size of tree: %d\n", sizeOfTree(root));
    return 0;
}

Don't cast malloc because return of malloc is void*.

不要转换malloc因为malloc的返回是void *。

#1