在PHP中创建具有不确定深度的多维数组

时间:2021-11-04 21:20:11

Good Evening - I am trying to create a multi-dimensional array based on an exploded text string of a account codes stored in the database. The account codes will be of varying lengths/depths. Say for example $test in the array below are similar to the results I would pull from the database:

晚上好 - 我正在尝试根据存储在数据库中的帐户代码的分解文本字符串创建一个多维数组。帐户代码将具有不同的长度/深度。比如说下面数组中的$ test类似于我从数据库中提取的结果:

$test = array( 
    '110|5100|120'    => 'Teacher Salaries',
    '110|5100|130'    => 'Other Professoinal Services',
    '110|5100|510|1'  => 'Primary Supplies',
    '110|5100|510|2'  => 'Intermediate Supplies', 
    '110|7300|110'    => 'Administrator Salaries', 
    '110|7300|510'    => 'Administrative Supplies', 
    '763|5100'        => 'Academic Grants'
); 
foreach($test AS $k => $v) { 
    $lvl = explode("|", $k);
    // Not sure what to do next... 
}

What I want to do is create a function which will return an array such as the following:

我想要做的是创建一个函数,它将返回一个如下所示的数组:

[110] => Array
    (
        [5100] => Array
            (
                [120] => Teacher Salaries
                [130] => Other Professional Services
                [510] => Array
                    (
                        [1] => Primary Supplies
                        [2] => Intermediate Supplies
                    )
            )
        [7300] => Array
            (
                [110] => Administrator Salaries
                [510] => Supplies
            )
    )
[763] => Array
    (
        [5100] => Academic Grants
    )

I was able to come up with a function that can take a single one of the codes and break it down correctly into an array, but when I try to merge them together, they lose their keys. Here is what I have so far:

我能够提出一个函数,它可以将一个代码中的一个代码正确地分解成一个数组,但是当我尝试将它们合并在一起时,它们会丢失它们的密钥。这是我到目前为止:

function expandedArray($codes, $value) { 
    $decoded = explode("|",$codes);
    RETURN expandedArraySub($decoded, $value); 
}
function expandedArraySub($decoded = array(), $value = Null) { 
    $k = array_pop($decoded); 
    $out[$k] = $value;
    if(is_array($decoded) && count($decoded) > 0) { $out = expandedArraySub($decoded, $out); }
    RETURN $out;
}

But when I run the following, instead of getting what I want as described above, I get an array that loses the "110" key:

但是,当我运行以下内容时,我得到一个丢失“110”键的数组,而不是如上所述得到我想要的内容:

$r1 = expandedArray('110|5100|510|1', "Primary Supplies"); 
  // $r1 is now [ 110 => [5100 => [510 => [ 1 ] ] ] ]
$r2 = expandedArray('110|5100|510|2', 'Intermediate Supplies'); 
  // $r2 is now [ 110 => [5100 => [510 => [ 2 ] ] ] ]
$r = array_merge($r1, $r2); 

The results I get remove the first key and doesn't combine the results as I was hoping. Here is what I get:

我得到的结果删除了第一个键,并没有像我希望的那样结合结果。这是我得到的:

[0] => Array
    (
        [5100] => Array
            (
                [510] => Array
                    (
                        [1] => Primary Supplies
                    )
            )
    )
[1] => Array
    (
        [5100] => Array
            (
                [510] => Array
                    (
                        [2] => Intermediate Supplies
                    )
            )
    )

Any help is much appreciated! Thanks!

任何帮助深表感谢!谢谢!

1 个解决方案

#1


1  

Try this code:

试试这段代码:

function getVal($data,$chain){
    $level = $data;
    for($i=0;$i<count($chain);$i++){
        if(isset($level[$chain[$i]]))
            $level = $level[$chain[$i]];
        else
            return null; // key does not exist, return null
    }
    return $level;
}

function setVal(&$data,$chain,$value){
    $level = &$data;
    for($i=0;$i<count($chain);$i++){
        $level = &$level[$chain[$i]]; // set reference (&) in order to change the value of the object
    }
    $level = $value;
}

For setting use it like this:

设置使用方式如下:

$output = array();
$test = array( 
    '110|5100|120'    => 'Teacher Salaries',
    '110|5100|130'    => 'Other Professoinal Services',
    '110|5100|510|1'  => 'Primary Supplies',
    '110|5100|510|2'  => 'Intermediate Supplies', 
    '110|7300|110'    => 'Administrator Salaries', 
    '110|7300|510'    => 'Administrative Supplies', 
    '763|5100'        => 'Academic Grants'
); 
foreach($test AS $k => $v) { 
    $lvl = explode("|", $k);
    setVal($output,$lvl,$v); 
}

$output should have the desired format.

$ output应该具有所需的格式。

Read more about this code in my previous post

在我之前的帖子中阅读有关此代码的更多信息

#1


1  

Try this code:

试试这段代码:

function getVal($data,$chain){
    $level = $data;
    for($i=0;$i<count($chain);$i++){
        if(isset($level[$chain[$i]]))
            $level = $level[$chain[$i]];
        else
            return null; // key does not exist, return null
    }
    return $level;
}

function setVal(&$data,$chain,$value){
    $level = &$data;
    for($i=0;$i<count($chain);$i++){
        $level = &$level[$chain[$i]]; // set reference (&) in order to change the value of the object
    }
    $level = $value;
}

For setting use it like this:

设置使用方式如下:

$output = array();
$test = array( 
    '110|5100|120'    => 'Teacher Salaries',
    '110|5100|130'    => 'Other Professoinal Services',
    '110|5100|510|1'  => 'Primary Supplies',
    '110|5100|510|2'  => 'Intermediate Supplies', 
    '110|7300|110'    => 'Administrator Salaries', 
    '110|7300|510'    => 'Administrative Supplies', 
    '763|5100'        => 'Academic Grants'
); 
foreach($test AS $k => $v) { 
    $lvl = explode("|", $k);
    setVal($output,$lvl,$v); 
}

$output should have the desired format.

$ output应该具有所需的格式。

Read more about this code in my previous post

在我之前的帖子中阅读有关此代码的更多信息