i'm not really much into MySQL, but i need just one statement and I would really appreciate your help on this.
我不是很喜欢MySQL,但是我只需要一个声明,非常感谢您在这方面的帮助。
I have two tables: 'user' and 'score'
我有两个表格,'user'和'score'
here's the structure of 'user':
这是“用户”的结构:
| user_id | user_name |
| 1 | Paul |
| 2 | Peter |
here's the structure of 'score':
这里是“score”的结构:
| score_id | score_user_id | score_track_id | score_points |
| 1 | 2 | 23 | 200 |
| 2 | 2 | 25 | 150 |
now I need a query that provides me some kind of highscore-list. the result should contain user_id, user_name and the sum of all scores that are related to the user: i should look like this:
现在,我需要一个查询来提供某种高级别列表。结果应该包含user_id、user_name以及与用户相关的所有分数之和:我应该如下所示:
| user_id | user_name | scores |
| 1 | Paul | 0 |
| 2 | Peter | 350 |
even better would be, if the result would be sorted in order of the users position in the global ranking like this:
如果结果按照用户在全球排名中的位置排序,情况会更好:
| position | user_id | user_name | scores |
| 1 | 2 | Peter | 350 |
| 2 | 1 | Paul | 0 |
I tried the statement
我试着声明
SELECT user_id as current_user, user_name, SUM(SELECT score_points FROM score WHERE score_user_id = current_user) as ranking FROM user ORDER BY ranking DESC
which results in a syntax error. the main problem for me is to connect the user_id from 'user' to the score_user_id in 'score' for each row.
这会导致语法错误。我的主要问题是将user_id从'user'连接到score_user_id(每个行的'score')。
thank you very much for your help
非常感谢你的帮助
1 个解决方案
#1
6
You just need to group your scores by user:
你只需要将你的分数按用户分组:
SELECT @p:=@p+1 AS position, t.*
FROM (
SELECT user.user_id,
user.user_name,
IFNULL(SUM(score.score_points),0) AS total_points
FROM user LEFT JOIN score ON user.user_id = score.score_user_id
GROUP BY user.user_id
ORDER BY total_points DESC
) AS t JOIN (SELECT @p:=0) AS initialisation
See it on sqlfiddle.
sqlfiddle上看到它。
#1
6
You just need to group your scores by user:
你只需要将你的分数按用户分组:
SELECT @p:=@p+1 AS position, t.*
FROM (
SELECT user.user_id,
user.user_name,
IFNULL(SUM(score.score_points),0) AS total_points
FROM user LEFT JOIN score ON user.user_id = score.score_user_id
GROUP BY user.user_id
ORDER BY total_points DESC
) AS t JOIN (SELECT @p:=0) AS initialisation
See it on sqlfiddle.
sqlfiddle上看到它。