This question already has an answer here:
这个问题在这里已有答案：
- How to return a part of an array in Ruby? 6 answers
- 如何在Ruby中返回数组的一部分？ 6个答案
My method:
我的方法：
def scroll_images
images_all[1..images_all.length]
end
I don't like that I'm calling images_all twice, just wondering if there's a good trick to call self or something similar to make this a little cleaner.
我不喜欢我两次调用images_all，只是想知道是否有一个很好的技巧来调用self或类似的东西来使它更清洁。
4 个解决方案
#1
8
Use -1 instead of the length:
使用-1而不是长度：
def scroll_images
images_all[1..-1] # `-1`: the last element, `1..-1`: The second to the last.
end
Example:
例：
a = [1, 2, 3, 4]
a[1..-1]
# => [2, 3, 4]
#2
11
You can get the same result in a clearer way using the Array#drop method:
您可以使用Array＃drop方法以更清晰的方式获得相同的结果：
a = [1, 2, 3, 4]
a.drop(1)
# => [2, 3, 4]
#3
1
If you're actually modifying the values of images_all i.e. explicitly drop the first element permanently, just use shift:
如果您实际上正在修改images_all的值，即明确地永久删除第一个元素，只需使用shift：
images_all.shift
#4
1
Here is one more way using Array#values_at :-
这是使用Array＃values_at的另一种方法： -
a = [1, 2, 3, 4]
a.values_at(1..-1) # => [2, 3, 4]
#1
8
Use -1 instead of the length:
使用-1而不是长度：
def scroll_images
images_all[1..-1] # `-1`: the last element, `1..-1`: The second to the last.
end
Example:
例：
a = [1, 2, 3, 4]
a[1..-1]
# => [2, 3, 4]
#2
11
You can get the same result in a clearer way using the Array#drop method:
您可以使用Array＃drop方法以更清晰的方式获得相同的结果：
a = [1, 2, 3, 4]
a.drop(1)
# => [2, 3, 4]
#3
1
If you're actually modifying the values of images_all i.e. explicitly drop the first element permanently, just use shift:
如果您实际上正在修改images_all的值，即明确地永久删除第一个元素，只需使用shift：
images_all.shift
#4
1
Here is one more way using Array#values_at :-
这是使用Array＃values_at的另一种方法： -
a = [1, 2, 3, 4]
a.values_at(1..-1) # => [2, 3, 4]