javascript Angularjs从数组中获取单个值

I'm quite new to angularjs and somehow theres something I can't make a workaround.

我对angularjs很新，不知何故，我无法解决这个问题。

Its getting a single value from a json array and then placing it in a scope variable. Lets say just got an array from a php query which looks like this (printed view):

它从json数组中获取单个值，然后将其放入范围变量中。让我们说从一个php查询得到一个数组看起来像这样（打印视图）：

array(
[name]   => John Doe,
[age]    => 29,
[gender] =>male);

And then it is added through this scope variable:

然后通过此范围变量添加：

$scope.profile = response.data;

How can I pick a single a value from that array and then place it separate scope variables?

如何从该数组中选择一个值，然后将其放在单独的范围变量中？

$scope.name; $scope.age; $scope.gender;

2 个解决方案

#1

Send your data back from your PHP using json_encode

使用json_encode从PHP发回数据

return json_encode($array);

which will then give you

然后会给你

object {
 name: 'John Doe',
 age: '29',
 gender: 'male'
}

And you can then access it using:

然后您可以使用以下方式访问它：

$scope.profile = response.data;
//
$scope.name   = $scope.profile.name;
$scope.age    = $scope.profile.age;
$scope.gender = $scope.profile.gender;

Example:

例：

var app = angular.module('someApp', [])
  .controller('someCtrl', function ($scope) {
    
    var object = {
      name: 'John Doe',
      age: '29',
      gender: 'male'
    };

    $scope.profile = object;
    
    $scope.name   = $scope.profile.name;
    $scope.age    = $scope.profile.age;
    $scope.gender = $scope.profile.gender;
    
  });

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="someApp" ng-controller="someCtrl">{{name}}, {{age}}, {{gender}}</div>

#2

$scope.name = response.data.name;
$scope.age = response.data.age;
$scope.gender = response.data.gender;

This should add them to the $scope.

这应该将它们添加到$ scope。

Make sure that the elements are in an object, not JSON string anymore.

确保元素在对象中，而不再是JSON字符串。

Or if you stay with the other one you already have:

或者，如果你和另一个人在一起，你已经拥有：

$scope.name = $scope.profile.name;
$scope.age = $scope.profile.age;
$scope.gender = $scope.profile.gender;

#1