I am using PHP to convert a list of postcodes + County into latitude and longitude. I have tried using the google map api and the simplexml_load_file() function like so:
我正在使用PHP将邮政编码+郡的列表转换为纬度和经度。我尝试使用谷歌映射api和simplexml_load_file()函数，如下所示:
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print"<pre>";
print_r($result);
Now this works fine as I am able to get the following:
现在这个方法很有效，因为我可以得到以下信息:
SimpleXMLElement Object
(
[status] => OK
[result] => SimpleXMLElement Object
(
[type] => postal_code
[formatted_address] => Walsall, Walsall, West Midlands WS9 8NS, UK
[address_component] => Array
(
[0] => SimpleXMLElement Object
(
[long_name] => WS9 8NS
[short_name] => WS9 8NS
[type] => postal_code
)
[1] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => Array
(
[0] => locality
[1] => political
)
)
[2] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => postal_town
)
[3] => SimpleXMLElement Object
(
[long_name] => West Midlands
[short_name] => West Mids
[type] => Array
(
[0] => administrative_area_level_2
[1] => political
)
)
[4] => SimpleXMLElement Object
(
[long_name] => United Kingdom
[short_name] => GB
[type] => Array
(
[0] => country
[1] => political
)
)
)
[geometry] => SimpleXMLElement Object
(
[location] => SimpleXMLElement Object
(
[lat] => 52.6030230
[lng] => -1.9175368
)
[location_type] => APPROXIMATE
[viewport] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6013713
[lng] => -1.9188871
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6040692
[lng] => -1.9161892
)
)
[bounds] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6020654
[lng] => -1.9182516
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6033751
[lng] => -1.9168247
)
)
)
)
)
Problem now is, how should I take out the first latitude / longitude and not the whole thing, I only need these two values.
现在的问题是，我应该如何取出第一个纬度/经度，而不是整个东西，我只需要这两个值。
Please note that the lat/long are dynamic as the address changes for each search.
请注意，lat/long是动态的，因为每次搜索的地址都在变化。
2 个解决方案
#1
2
From the print_r you can see the structure of the content. Then, it is a matter of following it.
从print_r中可以看到内容的结构。那么，这就是遵循它的问题。
This contains the values:
这包含的值:
$result->result->geometry->location
So to print them separately, you can say:
要分开打印，你可以说:
print "lat: " . $result->result->geometry->location->lat;
print "lng: " . $result->result->geometry->location->lng;
All together:
在一起:
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print "lat: " . $result->result->geometry->location->lat . " <br/>";
print "lng: " . $result->result->geometry->location->lng . " <br/>";
#2
2
Better to use their JSON API.
最好使用它们的JSON API。
$url ="http://maps.googleapis.com/maps/api/geocode/json?address=WS9+8NS,+West+Midlands&sensor=false";
$result = file_get_contents($url);
print"<pre>";
$resultArray = json_decode($result, true);
print_r($result);
Then just access like an array!
然后像访问数组一样访问!
e.g.
如。
$resultArray['results']['geometry']['location']['lat']
$resultArray['results']['geometry']['location']['lng']
I would use cURL instead of file get contents as it gives more control. But this works fine.
我将使用cURL而不是file get内容，因为它提供了更多的控制。但这没问题。
I would also check the $resultArray before attempting to do anything with it.
我还将检查$resultArray，然后再尝试使用它。
#1
2
From the print_r you can see the structure of the content. Then, it is a matter of following it.
从print_r中可以看到内容的结构。那么，这就是遵循它的问题。
This contains the values:
这包含的值:
$result->result->geometry->location
So to print them separately, you can say:
要分开打印，你可以说:
print "lat: " . $result->result->geometry->location->lat;
print "lng: " . $result->result->geometry->location->lng;
All together:
在一起:
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print "lat: " . $result->result->geometry->location->lat . " <br/>";
print "lng: " . $result->result->geometry->location->lng . " <br/>";
#2
2
Better to use their JSON API.
最好使用它们的JSON API。
$url ="http://maps.googleapis.com/maps/api/geocode/json?address=WS9+8NS,+West+Midlands&sensor=false";
$result = file_get_contents($url);
print"<pre>";
$resultArray = json_decode($result, true);
print_r($result);
Then just access like an array!
然后像访问数组一样访问!
e.g.
如。
$resultArray['results']['geometry']['location']['lat']
$resultArray['results']['geometry']['location']['lng']
I would use cURL instead of file get contents as it gives more control. But this works fine.
我将使用cURL而不是file get内容，因为它提供了更多的控制。但这没问题。
I would also check the $resultArray before attempting to do anything with it.
我还将检查$resultArray，然后再尝试使用它。