I have a string:
我有一个字符串:
s <- "test.test AS field1, ablh.blah AS field2, faslk.lsdf AS field3"
I want to convert to:
我想转换为:
"field1, field2, field3"
I know that the regular expression (\w+)(?:,|$)
will extract the strings I want ('field1,' etc) but I can't figure out how to extract it with gsub
.
我知道正则表达式(\ w +)(?:,| $)将提取我想要的字符串('field1,'等),但我无法弄清楚如何用gsub提取它。
2 个解决方案
#1
10
## Preparation
s <- "test.test AS field1, ablh.blah AS field2, faslk.lsdf AS field3"
pat <- "(\\w+)(?:,|$)" ## Note the doubly-escaped \\w
## Use the powerful gregexpr/regmatches one-two punch
m <- gregexpr(pat, s)
paste(regmatches(s, m)[[1]], collapse=" ")
# [1] "field1, field2, field3"
#2
0
With strapplyc
in the gsubfn package one can do it with a particularly simple regular expression which extracts each string of word characters that follows " AS "
(If the field can contain non-word characters then replace \\w
with the appropriate expression, for example any char that is not a space or comma: [^ ,]
):
使用gsubfn包中的strapplyc,可以使用一个特别简单的正则表达式来完成它,该正则表达式提取“AS”后面的每个单词字符串(如果该字段可以包含非单词字符,则用适当的表达式替换\\ w,例如任何不是空格或逗号的字符:[^,]):
> library(gsubfn)
> strapplyc(s, " AS (\\w+)", simplify = toString)[[1]]
[1] "field1, field2, field3"
#1
10
## Preparation
s <- "test.test AS field1, ablh.blah AS field2, faslk.lsdf AS field3"
pat <- "(\\w+)(?:,|$)" ## Note the doubly-escaped \\w
## Use the powerful gregexpr/regmatches one-two punch
m <- gregexpr(pat, s)
paste(regmatches(s, m)[[1]], collapse=" ")
# [1] "field1, field2, field3"
#2
0
With strapplyc
in the gsubfn package one can do it with a particularly simple regular expression which extracts each string of word characters that follows " AS "
(If the field can contain non-word characters then replace \\w
with the appropriate expression, for example any char that is not a space or comma: [^ ,]
):
使用gsubfn包中的strapplyc,可以使用一个特别简单的正则表达式来完成它,该正则表达式提取“AS”后面的每个单词字符串(如果该字段可以包含非单词字符,则用适当的表达式替换\\ w,例如任何不是空格或逗号的字符:[^,]):
> library(gsubfn)
> strapplyc(s, " AS (\\w+)", simplify = toString)[[1]]
[1] "field1, field2, field3"