Can I add protocol conformance to a protocol via a swift extension?
我可以通过快速扩展将协议一致性添加到协议中吗?
//Plain old protocol here
protocol MyData {
var myDataID: Int { get }
}
I want to make the MyData
protocol equatable by default (just compare the ID)
我想默认使MyData协议相等(只需比较ID)
extension MyData : Equatable { }
But I get this lovely error:
但我得到了这个可爱的错误:
"Extension of protocol 'MyData' cannot have an inheritance clause"
“协议扩展'MyData'不能有继承子句”
The behavior i'm looking is BananaData conforming to Equatable (a protocol) because it implements the MyData protocol which can provide a default implementation of Equatable
我正在寻找的行为是符合Equatable(协议)的BananaData,因为它实现了MyData协议,它可以提供Equatable的默认实现
//This is the method to implement Equatable
func ==(lhs: MyData, rhs: MyData) -> Bool {
return lhs.myDataID == rhs.myDataID
}
struct BananaData: MyData {
var myDataID: Int = 1
}
func checkEquatable(bananaOne: BananaData, bananaTwo: BananaData) {
//This compiles, verifying that BananaData can be compared
if bananaOne == bananaTwo { }
//But BananaData is not convertible to Equatable, which is what I want
let equatableBanana = bananaOne as Equatable
//I don't get the additional operations added to Equatable (!=)
if bananaOne != bananaTwo { } //Error
}
2 个解决方案
#1
23
As the error message says: an extension of a protocol cannot have an inheritance clause. Instead, you could make MyData
protocol inherit from Equatable
in the original declaration.
正如错误消息所示:协议的扩展不能具有继承子句。相反,您可以在原始声明中使MyData协议继承自Equatable。
protocol MyData: Equatable {
var myDataID: Int { get }
}
You could then extend add an implementation of ==
for types that conform to MyData
:
然后,您可以为符合MyData的类型扩展添加==的实现:
func == <T: MyData>(lhs: T, rhs: T) -> Bool {
return lhs.myDataID == rhs.myDataID
}
However, I would highly not recommend this! If you add more properties to conforming types, their properties won't be checked for equality. Take the example below:
但是,我强烈不推荐这个!如果向符合类型添加更多属性,则不会检查其属性是否相等。以下面的例子为例:
struct SomeData: MyData {
var myDataID: Int
var myOtherData: String
}
let b1 = SomeData(myDataID: 1, myOtherData: "String1")
let b2 = SomeData(myDataID: 1, myOtherData: "String2")
b1 == b2 // true, although `myOtherData` properties aren't equal.
In the case above you'd need to override ==
for SomeData
for the correct result, thus making the ==
that accepts MyData
redundant.
在上面的情况中,您需要为SomeData重写==以获得正确的结果,从而使接受MyData的==变为冗余。
#2
2
Does this playground do what you want? I made it based on what I understand from Protocol-Oriented Programming in Swift from WWDC 2015.
这个游乐场能做你想做的吗?我是根据我从WWDC 2015中的Swift中面向协议编程中所理解的内容来完成的。
import Foundation
//Plain old protocol here
func == (lhs: MyData, rhs: MyData) -> Bool {
return lhs.myDataID == rhs.myDataID
}
func != (lhs: MyData, rhs: MyData) -> Bool {
return lhs.myDataID != rhs.myDataID
}
protocol MyData {
var myDataID: Int { get }
}
extension MyData where Self: Equatable {
}
struct BananaData: MyData {
var myDataID: Int = 1
}
func checkEquatable(bananaOne: BananaData, bananaTwo: BananaData) {
//This compiles, verifying that BananaData can be compared
if bananaOne == bananaTwo {
print("Same")
}
//But BananaData is not convertible to Equatable, which is what I want
//I don't get the additional operations added to Equatable (!=)
print(bananaOne.myDataID)
print(bananaTwo.myDataID)
if bananaOne != bananaTwo {
}
//Error
}
let b1 = BananaData(myDataID: 2)
let b2 = BananaData(myDataID: 2)
checkEquatable(b1, bananaTwo: b2)
let c = b1 == b2 // Evaluates as true
#1
23
As the error message says: an extension of a protocol cannot have an inheritance clause. Instead, you could make MyData
protocol inherit from Equatable
in the original declaration.
正如错误消息所示:协议的扩展不能具有继承子句。相反,您可以在原始声明中使MyData协议继承自Equatable。
protocol MyData: Equatable {
var myDataID: Int { get }
}
You could then extend add an implementation of ==
for types that conform to MyData
:
然后,您可以为符合MyData的类型扩展添加==的实现:
func == <T: MyData>(lhs: T, rhs: T) -> Bool {
return lhs.myDataID == rhs.myDataID
}
However, I would highly not recommend this! If you add more properties to conforming types, their properties won't be checked for equality. Take the example below:
但是,我强烈不推荐这个!如果向符合类型添加更多属性,则不会检查其属性是否相等。以下面的例子为例:
struct SomeData: MyData {
var myDataID: Int
var myOtherData: String
}
let b1 = SomeData(myDataID: 1, myOtherData: "String1")
let b2 = SomeData(myDataID: 1, myOtherData: "String2")
b1 == b2 // true, although `myOtherData` properties aren't equal.
In the case above you'd need to override ==
for SomeData
for the correct result, thus making the ==
that accepts MyData
redundant.
在上面的情况中,您需要为SomeData重写==以获得正确的结果,从而使接受MyData的==变为冗余。
#2
2
Does this playground do what you want? I made it based on what I understand from Protocol-Oriented Programming in Swift from WWDC 2015.
这个游乐场能做你想做的吗?我是根据我从WWDC 2015中的Swift中面向协议编程中所理解的内容来完成的。
import Foundation
//Plain old protocol here
func == (lhs: MyData, rhs: MyData) -> Bool {
return lhs.myDataID == rhs.myDataID
}
func != (lhs: MyData, rhs: MyData) -> Bool {
return lhs.myDataID != rhs.myDataID
}
protocol MyData {
var myDataID: Int { get }
}
extension MyData where Self: Equatable {
}
struct BananaData: MyData {
var myDataID: Int = 1
}
func checkEquatable(bananaOne: BananaData, bananaTwo: BananaData) {
//This compiles, verifying that BananaData can be compared
if bananaOne == bananaTwo {
print("Same")
}
//But BananaData is not convertible to Equatable, which is what I want
//I don't get the additional operations added to Equatable (!=)
print(bananaOne.myDataID)
print(bananaTwo.myDataID)
if bananaOne != bananaTwo {
}
//Error
}
let b1 = BananaData(myDataID: 2)
let b2 = BananaData(myDataID: 2)
checkEquatable(b1, bananaTwo: b2)
let c = b1 == b2 // Evaluates as true