I'm having a tough time figuring out how to get this structure array to appear as a single string "c_str" when I use the printf function. As of now I only can only get c_str to be one part of the line structure array, in this case the 24th line. When I use print(c_str); i would like the output to display all of the data that is in the code. It needs to be stored as a string because I have a function that needs to access n,m,gnm,hnm,dgnm, and dhnm.
当我使用printf函数时，我很难弄清楚如何让这个结构数组作为一个字符串“c_str”出现。现在我只能让c_str成为行结构数组的一部分，在这个例子中是第24行。当我使用打印(c_str);我希望输出显示代码中所有的数据。它需要被存储为一个字符串，因为我有一个函数需要访问n、m、gnm、hnm、dgnm和dhnm。
Thank you for the help
谢谢你的帮助。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
int main()
{
int i=0,n[90],m[90];
float gnm[90],hnm[90],dgnm[90],dhnm[90];
static char c_str[90];
struct wmm
{
int n;
int m;
float gnm;
float hnm;
float dgnm;
float dhnm;
} book[90]= {{1, 0, -29496.6, 0.0, 11.6, 0.0},
{1, 1, -1586.3, 4944.4, 16.5, -25.9},
{2, 0, -2396.6, 0.0, -12.1, 0.0},
{2, 1, 3026.1, -2707.7, -4.4, -22.5},
{2, 2, 1668.6, -576.1, 1.9, -11.8},
{3, 0, 1340.1, 0.0, 0.4, 0.0},
{3, 1, -2326.2, -160.2, -4.1, 7.3},
{3, 2, 1231.9, 251.9, -2.9, -3.9},
{3, 3, 634.0, -536.6, -7.7, -2.6},
{4, 0, 912.6, 0.0, -1.8, 0.0},
{4, 1, 808.9, 286.4, 2.3, 1.1},
{4, 2, 166.7, -211.2, -8.7, 2.7},
{4, 3, -357.1, 164.3, 4.6, 3.9},
{4, 4, 89.4, -309.1, -2.1, -0.8},
{5, 0, -230.9, 0.0, -1.0, 0.0},
{5, 1, 357.2, 44.6, 0.6, 0.4},
{5, 2, 200.3, 188.9, -1.8, 1.8},
{5, 3, -141.1, -118.2, -1.0, 1.2},
{5, 4, -163.0, 0.0, 0.9, 4.0},
{5, 5, -7.8, 100.9, 1.0, -0.6},
{6, 0, 72.8, 0.0, -0.2, 0.0},
{6, 1, 68.6, -20.8, -0.2, -0.2},
{6, 2, 76.0, 44.1, -0.1, -2.1},
{6, 3, -141.4, 61.5 , 2.0, -0.4},
{6, 4, -22.8, -66.3, -1.7, -0.6},
{6, 5, 13.2, 3.1, -0.3, 0.5},
{6, 6, -77.9, 55.0, 1.7, 0.9},
{7, 0, 80.5, 0.0, 0.1, 0.0},
{7, 1, -75.1, -57.9, -0.1, 0.7},
{7, 2, -4.7, -21.1, -0.6, 0.3},
{7, 3, 45.3, 6.5, 1.3, -0.1},
{7, 4, 13.9, 24.9, 0.4, -0.1},
{7, 5, 10.4, 7.0, 0.3, -0.8},
{7, 6, 1.7, -27.7, -0.7, -0.3},
{7, 7, 4.9, -3.3, 0.6, 0.3},
{8, 0, 24.4, 0.0, -0.1, 0.0},
{8, 1, 8.1, 11.0, 0.1, -0.1},
{8, 2, -14.5, -20.0, -0.6, 0.2},
{8, 3, -5.6, 11.9, 0.2, 0.4},
{8, 4, -19.3, -17.4, -0.2, 0.4},
{8, 5, 11.5, 16.7, 0.3, 0.1},
{8, 6, 10.9, 7.0, 0.3, -0.1},
{8, 7, -14.1, -10.8, -0.6, 0.4},
{8, 8, -3.7, 1.7, 0.2, 0.3},
{9, 0, 5.4, 0.0, 0.0, 0.0},
{9, 1, 9.4, -20.5, -0.1, 0.0},
{9, 2, 3.4, 11.5, 0.0, -0.2},
{9, 3, -5.2, 12.8, 0.3, 0.0},
{9, 4, 3.1, -7.2, -0.4, -0.1},
{9, 5, -12.4, -7.4, -0.3, 0.1},
{9, 6, -0.7, 8.0, 0.1, 0.0},
{9, 7, 8.4, 2.1, -0.1, -0.2},
{9, 8, -8.5, -6.1, -0.4, 0.3},
{9, 9, -10.1, 7.0, -0.2, 0.2},
{10, 0, -2.0, 0.0, 0.0, 0.0},
{10, 1, -6.3, 2.8, 0.0, 0.1},
{10, 2 , 0.9 , -0.1 , -0.1 , -0.1},
{10, 3, -1.1, 4.7, 0.2, 0.0},
{10, 4, -0.2, 4.4, 0.0, -0.1},
{10, 5, 2.5, -7.2, -0.1, -0.1},
{10, 6, -0.3, -1.0 , -0.2 , 0.0},
{10, 7, 2.2, -3.9, 0.0, -0.1},
{10, 8, 3.1, -2.0, -0.1, -0.2},
{10, 9, -1.0, -2.0, -0.2, 0.0},
{10, 10, -2.8, -8.3, -0.2, -0.1},
{11, 0, 3.0, 0.0, 0.0, 0.0},
{11, 1, -1.5, 0.2, 0.0, 0.0},
{11, 2, -2.1, 1.7, 0.0, 0.1},
{11, 3, 1.7, -0.6, 0.1, 0.0},
{11, 4, -0.5, -1.8, 0.0, 0.1},
{11, 5, 0.5, 0.9, 0.0, 0.0},
{11, 6, -0.8, -0.4, 0.0, 0.1},
{11, 7, 0.4, -2.5, 0.0, 0.0},
{11, 8, 1.8, -1.3, 0.0, -0.1},
{11, 9, 0.1, -2.1, 0.0, -0.1},
{11, 10, 0.7, -1.9, -0.1, 0.0},
{11, 11, 3.8, -1.8, 0.0, -0.1},
{12, 0, -2.2, 0.0, 0.0, 0.0},
{12, 1, -0.2, -0.9, 0.0, 0.0},
{12, 2, 0.3, 0.3, 0.1, 0.0},
{12, 3, 1.0 , 2.1 , 0.1 , 0.0},
{12, 4, -0.6, -2.5, -0.1, 0.0},
{12, 5, 0.9, 0.5, 0.0, 0.0},
{12, 6, -0.1, 0.6, 0.0, 0.1},
{12, 7, 0.5, 0.0, 0.0, 0.0},
{12, 8, -0.4, 0.1, 0.0, 0.0},
{12, 9, -0.4, 0.3, 0.0, 0.0},
{12, 10, 0.2, -0.9, 0.0, 0.0},
{12, 11, -0.8, -0.2, -0.1, 0.0},
{12, 12, 0.0, 0.9, 0.1, 0.0}};
sprintf(c_str, " %d %d %lf %lf %lf %lf" ,book[25].n, book[25].m , book[25].gnm , book[25].hnm, book[25].dgnm, book[25].dhnm);
getchar();
return 0;
}
1 个解决方案
#1
2
If you are trying to copy all of the data in the struct into c_str, you only need to wrap sprintf() in a loop. Note that you should really switch to snprintf() to avoid accidentally introducing a buffer-overflow.
如果您试图将struct中的所有数据复制到c_str，那么只需将sprintf()包装在一个循环中即可。注意，您应该真正切换到snprintf()，以避免意外地引入缓冲区溢出。
Since sprintf() and snprintf() return the number of character that they add to the string, you can easily keep track of the next unused location in the string:
由于sprintf()和snprintf()返回它们添加到字符串中的字符数量，您可以轻松地跟踪字符串中下一个未使用的位置:
int i, n = 90, buf_size = 90, offset = 0;
for (i = 0; i < n && offset < buf_size; ++i) {
offset += snprintf(c_str + offset, buf_size - offset, " %d %d %lf %lf %lf %lf", book[i].n, book[i].m , book[i].gnm , book[i].hnm, book[i].dgnm, book[i].dhnm);
}
If you were to repeatedly pass c_str as the first argument, it would only contain the last line.
如果您要重复地将c_str作为第一个参数，那么它只包含最后一行。
#1
2
If you are trying to copy all of the data in the struct into c_str, you only need to wrap sprintf() in a loop. Note that you should really switch to snprintf() to avoid accidentally introducing a buffer-overflow.
如果您试图将struct中的所有数据复制到c_str，那么只需将sprintf()包装在一个循环中即可。注意，您应该真正切换到snprintf()，以避免意外地引入缓冲区溢出。
Since sprintf() and snprintf() return the number of character that they add to the string, you can easily keep track of the next unused location in the string:
由于sprintf()和snprintf()返回它们添加到字符串中的字符数量，您可以轻松地跟踪字符串中下一个未使用的位置:
int i, n = 90, buf_size = 90, offset = 0;
for (i = 0; i < n && offset < buf_size; ++i) {
offset += snprintf(c_str + offset, buf_size - offset, " %d %d %lf %lf %lf %lf", book[i].n, book[i].m , book[i].gnm , book[i].hnm, book[i].dgnm, book[i].dhnm);
}
If you were to repeatedly pass c_str as the first argument, it would only contain the last line.
如果您要重复地将c_str作为第一个参数，那么它只包含最后一行。