Let's say I have a hash in Ruby like this:
假设我在Ruby中有一个哈希，就像这样：
d = {1 => 'one', 3 => 'three', 2 =>'two'}
and I wish to get
我希望得到
x = [1, 2, 3]
y = ['one', 'two', 'three']
that is, I want the sorted keys in x, and the corresponding values in y. I potentially want to use a custom sort order for x.
也就是说，我希望x中的排序键和y中的相应值。我可能想要使用x的自定义排序顺序。
What's the cleanest, simplest way to do this?
什么是最干净，最简单的方法？
3 个解决方案
#1
8
Easy:
简单：
x,y = d.sort.transpose
Or, with a custom sort:
或者，使用自定义排序：
x,y = d.sort_by {|k,v| whatever}.transpose
#2
8
my original answer
我的原始答案
x = d.keys.sort
y = x.map {|k| d[k]}
but you should also see glenn mcdonald's answer
但你也应该看到格伦麦克唐纳的回答
x,y = d.sort.transpose
#3
0
x, y = d.keys.sort{|a,b| a <=> b}.inject([]){|result, key| result << [key, d[key]]}.transpose
... made the sort explicit so you can change it to whatever you like.
...明确排序，以便您可以将其更改为您喜欢的任何内容。
#1
8
Easy:
简单：
x,y = d.sort.transpose
Or, with a custom sort:
或者，使用自定义排序：
x,y = d.sort_by {|k,v| whatever}.transpose
#2
8
my original answer
我的原始答案
x = d.keys.sort
y = x.map {|k| d[k]}
but you should also see glenn mcdonald's answer
但你也应该看到格伦麦克唐纳的回答
x,y = d.sort.transpose
#3
0
x, y = d.keys.sort{|a,b| a <=> b}.inject([]){|result, key| result << [key, d[key]]}.transpose
... made the sort explicit so you can change it to whatever you like.
...明确排序，以便您可以将其更改为您喜欢的任何内容。