Getting the above error on the following script:
在以下脚本上获得上述错误:
DROP TABLE IF EXISTS `incident`;
SET @saved_cs_client = @@character_set_client;
SET character_set_client = utf8;
CREATE TABLE `incident` (
`incident_id` int(11) NOT NULL auto_increment,
`patient_id` int(11) default NULL,
`history_id` int(11) default NULL,
`incident_date` datetime default NULL,
`incidentname_id` int(11) default NULL,
`incident_type_id` int(11) default NULL,
`pop_first_symptom` int(11) default NULL,
`first_symptom_date` datetime default NULL,
`similar_symptom_date` datetime default NULL,
`first_consultation_date` datetime default NULL,
`accident` int(1) default NULL,
`accident_date` datetime default NULL,
`pop_accident_state` int(11) default NULL,
`pop_condition_related_to` int(11) default NULL,
`flag_prothesis` char(1) collate utf8_unicode_ci NOT NULL default '0',
`flag_initial_placement` char(1) collate utf8_unicode_ci NOT NULL default '0',
`flag_orthodontics` char(1) collate utf8_unicode_ci NOT NULL default '0',
`flag_occupational_illness` char(1) collate utf8_unicode_ci NOT NULL default '0',
`box19` varchar(80) collate utf8_unicode_ci NOT NULL default '',
`color` varchar(8) collate utf8_unicode_ci NOT NULL default 'ffffff00',
`referrals_id` int(11) default NULL,
`referral_date` datetime default NULL,
`facility_id` int(11) default NULL,
`attorney_id` int(11) default NULL,
`attorney_notes` text collate utf8_unicode_ci,
`attorney_report_sent` date default NULL,
`attorney_deposition_date` date default NULL,
`attorney_trial_date` date default NULL,
`attorney_notice_filing` char(1) collate utf8_unicode_ci default NULL,
`attorney_final_settlement` date default NULL,
`effective_date` datetime default NULL,
`termination_date` datetime default NULL,
`date` datetime default NULL,
`pop_branch` int(11) default NULL,
`pop_status` int(1) default NULL,
`pop_eligibility` int(1) default NULL,
`partial_begin_date` datetime default NULL,
`partial_end_date` datetime default NULL,
`last_work_date` datetime default NULL,
`partial_return_to_work_date` datetime default NULL,
`total_begin_date` datetime default NULL,
`total_end_date` datetime default NULL,
`last_xray_date` datetime default NULL,
`last_seen_date` date default NULL,
`assumed_date` datetime default NULL,
`relinquished_date` datetime default NULL,
`radiographs` varchar(30) collate utf8_unicode_ci NOT NULL default '',
`oral_images` varchar(30) collate utf8_unicode_ci NOT NULL default '',
`models` varchar(30) collate utf8_unicode_ci NOT NULL default '',
`date_appliance_placed` date default NULL,
`date_prior_placement` date default NULL,
`paymentSourceCode` varchar(10) collate utf8_unicode_ci NOT NULL default '',
`locatorCode` varchar(10) collate utf8_unicode_ci NOT NULL default '',
`SAExceptionCode` varchar(10) collate utf8_unicode_ci NOT NULL default '',
`flag_expanded` int(1) default NULL,
`flag_archived` int(1) default NULL,
`cda_reason_code` int(11) default NULL,
`is_extraction` int(11) default '0',
`extraction_tooth` varchar(10) collate utf8_unicode_ci default NULL,
`initial_placement_date` date default NULL,
`initial_placement_location` int(11) default '0',
`prosthesis_material` int(11) default '0',
PRIMARY KEY (`incident_id`),
KEY `patient_id_key` (`patient_id`),
CONSTRAINT `incident_ibfk_1` FOREIGN KEY (`patient_id`) REFERENCES `patient` (`patient_id`)
) ENGINE=InnoDB AUTO_INCREMENT=9854 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
SET character_set_client = @saved_cs_client;
Here is the patient table giving me the same error:
这是患者表给我同样的错误:
DROP TABLE IF EXISTS `patient`;
SET @saved_cs_client = @@character_set_client;
SET character_set_client = utf8;
CREATE TABLE `patient` (
`patient_id` int(11) NOT NULL auto_increment,
`history_id` int(11) default NULL,
`person_id` int(11) default NULL,
`account_id` int(11) default NULL,
`display_id` varchar(10) collate utf8_unicode_ci default NULL,
`chart_num` varchar(10) collate utf8_unicode_ci default NULL,
`bridge_num` varchar(10) collate utf8_unicode_ci default NULL,
`provider_id` int(11) default NULL,
`office_id` int(11) default NULL,
`feeschedule_id` int(11) default NULL,
`pop_marital_status` int(11) default NULL,
`pop_employment` int(11) default NULL,
`new_patient_date` date default NULL,
`primary_ins_id` int(11) default NULL,
`primary_ins_type` char(1) collate utf8_unicode_ci default NULL,
`insured_id_number` varchar(30) collate utf8_unicode_ci default NULL,
`flag_special_insurance` char(1) collate utf8_unicode_ci default '0',
`flag_family_planning` char(1) collate utf8_unicode_ci default '0',
`flag_epstd` char(1) collate utf8_unicode_ci default '0',
`pop_relation_to_primary` int(11) default NULL,
`pop_relation_to_secondary` int(11) default NULL,
`pop_hipaa_release` int(11) default NULL,
`hipaa_release_date` date default NULL,
`patientNotes` text collate utf8_unicode_ci,
`autoremind_notification_type_id` int(11) NOT NULL default '0',
`ethnicity_id` int(11) default NULL,
`patient_status` int(1) NOT NULL default '0',
`created_by_module` char(1) collate utf8_unicode_ci NOT NULL default 'P',
`pop_patient_exception_code` int(11) default '0',
`pop_native_language` int(11) default '0',
`school_name` varchar(30) collate utf8_unicode_ci default NULL,
`graduation_date` date default NULL,
`hygienist_id` int(11) default NULL,
`school_address_id` int(11) default NULL,
`language_id` int(11) default NULL,
PRIMARY KEY (`patient_id`),
KEY `account_id_key` (`account_id`),
KEY `person_id_key` (`person_id`),
KEY `patient_status_index` (`patient_status`),
KEY `person_id_index` (`person_id`),
KEY `account_id_index` (`account_id`),
CONSTRAINT `patient_ibfk_1` FOREIGN KEY (`account_id`) REFERENCES `account` (`account_id`),
CONSTRAINT `patient_ibfk_2` FOREIGN KEY (`person_id`) REFERENCES `person` (`person_id`)
) ENGINE=InnoDB AUTO_INCREMENT=9855 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
SET character_set_client = @saved_cs_client;
1 个解决方案
#1
0
I assume that your foreign key patient_id
is not NULL
. It must match to your referenced data type.
我假设你的外键patient_id不是NULL。它必须与您引用的数据类型匹配。
`patient_id` int(11) default NULL
#1
0
I assume that your foreign key patient_id
is not NULL
. It must match to your referenced data type.
我假设你的外键patient_id不是NULL。它必须与您引用的数据类型匹配。
`patient_id` int(11) default NULL