最近在一组SQL中输入

I have Table in which We can have Same ticket no.for multiple entries.i want to retrieve most recent ticket(of same ticket no.) number based on Initiated on column.

我有一个表,其中我们可以为多个条目提供相同的票号。我想根据列上的“已启动”检索最近的票证(相同票号)。

Ticket  VendorTicket  InitiatedOn              Comments
198165  test          2012-08-10 16:31:33.707  test
199485  sagar         2012-08-11 12:36:25.720  sagar
199485  sagar1        2012-08-11 14:36:25.720  sagar1
199478  kishor        2012-08-11 12:37:21.923  kishor

I have Written this query in T-SQL in Stored Procedure It gives me Error Saying xObj = {"Incorrect syntax near '.'."}

我已经在存储过程中的T-SQL中编写了这个查询它给了我错误说xObj = {“''附近的语法不正确。”。}

My T-SQL

`@SQL='Select ''<a href="javascript:editTicketByIDAction('' + CONVERT(VarChar(Max), Ticket) + '')">'' + CONVERT(VarChar(Max),Ticket) + ''</a>'' t1.Ticket,t1.VendorTicket[Vendor Ticket],t1.Comments 
From VendorTickets t1 
WHERE NotifyOn <= GetDate() And NotifyOn Is Not Null AND 
NOT EXISTS
(SELECT * FROM VendorTickets t2 
WHERE t1.Ticket = t2.Ticket AND t1.InitiatedOn < t2.InitiatedOn)'`

6 个解决方案

#1

A general solution (works on any database) to this problem is the following:

此问题的一般解决方案(适用于任何数据库)如下:

SELECT * FROM [my_table] t1
WHERE NOT EXISTS (
  SELECT * FROM [my_table] t2
  WHERE t1.Ticket = t2.Ticket
  AND t1.InitiatedOn < t2.InitiatedOn
)

This reads: Get all value from my_table where there is no ticket with the same Ticket ID and a more recent date.

其内容如下:从my_table获取所有值,其中没有具有相同故障单ID和更新日期的故障单。

Notes:

This may return duplicates in case there are two "most recent" tickets with identical InitiatedOn value.

如果有两个具有相同InitiatedOn值的“最新”票证,则可能会返回重复项。

Be sure to have appropriate indexes on both Ticket and InitiatedOn columns

确保Ticket和InitiatedOn列上都有适当的索引

#2

try this:

This will give most recent records from each group

这将给出每组的最新记录

select * from  <table> t join
(select Ticket,max(InitiatedOn) as InitiatedOn
from <table>
group by Ticket)a
on t.Ticket=a.Ticket
and t.InitiatedOn=a.InitiatedOn

#3

SELECT   Ticket,
         VendorTicket,
         InitiatedOn,
         Comments
FROM     (
         SELECT   Ticket,
                  VendorTicket,
                  InitiatedOn,
                  Comments, 
                  ROW_NUMBER() OVER (PARTITION BY Ticket ORDER BY InitiatedOn DESC) AS Row
         FROM     Table
         ) AS Q
WHERE    Q.Row = 1

#4

If row_number() over() is available for you.

如果row_number()over()可用。

select T.Ticket,
       T.VendorTicket,
       T.InitiatedOn,
       T.Comments
from (
     select Ticket,
            VendorTicket,
            InitiatedOn,
            Comments,
            row_number() over(partition by Ticket order by InitiatedOn desc) as rn
     from YourTable
     ) T
where T.rn = 1

#5

Select t1.* 
from tickets t1 
left join tickets t2 on (t1.ticket = t2.ticket and t2.initiatedon > t1.initiatedon)
where t2.ticket is null;

#6

-1

select * from table where ticket=199485 order by InitiatedOn desc limit 1;

#1