I have two tables:
我有两张桌子:
t1:
cust_id email
201 email1@sadpanda.com
202 email2@email.com
203 email3@sadpanda.com
t2:
cust_id value
201 dfceaa64f8b93661903a849b09c5ac4e10abdfed21763a04d6eb9523e02d6dc1:Qs
202 c15af11e5acb2f6b7e7b12ab7eee8ce482f0cf76f76b7e65dde6b15c3a910680:Qx
203 71ae98d020b16f6f668db6bde3f9c18350a892b55736995237fa71aa5dc2b206:MU
I would like to select from 't1' where email is like 'sadpanda' and receive the values for those users from 't2'. Should I be using an inner join for this?
我想从't1'中选择电子邮件就像'sadpanda',并从't2'接收这些用户的值。我应该使用内部联接吗?
2 个解决方案
#1
0
SELECT t2.*
FROM t2
JOIN t1 USING (cust_id)
WHERE t1.email = 'email3@sadpanda.com'
SQL小提琴示例
#2
0
you may have two ways to do it 1. you can use simple join query . something like
你可能有两种方法可以做到1.你可以使用简单的连接查询。就像是
SELECT T2.*
FROM T1 JOIN T2 ON T.CUST_ID = T2.CUST_ID
WHERE T1.EMAIL LIKE '%sadpanda%'
-
or you can use subquery something like
或者你可以使用子查询之类的东西
SELECT T2.* FROM T2 WHERE CUST_ID IN (SELECT CUST_ID FROM T1 WHERE T1.EMAIL LIKE '%sadpanda%')
SELECT T2。* FROM T2 WHERE CUST_ID IN(从T1选择CUST_ID T1.EMAIL LIKE'%sadpanda%')
I suggest first one . it will run faster then second one .
我建议先做一个。它将比第二个运行得更快。
#1
0
SELECT t2.*
FROM t2
JOIN t1 USING (cust_id)
WHERE t1.email = 'email3@sadpanda.com'
SQL小提琴示例
#2
0
you may have two ways to do it 1. you can use simple join query . something like
你可能有两种方法可以做到1.你可以使用简单的连接查询。就像是
SELECT T2.*
FROM T1 JOIN T2 ON T.CUST_ID = T2.CUST_ID
WHERE T1.EMAIL LIKE '%sadpanda%'
-
or you can use subquery something like
或者你可以使用子查询之类的东西
SELECT T2.* FROM T2 WHERE CUST_ID IN (SELECT CUST_ID FROM T1 WHERE T1.EMAIL LIKE '%sadpanda%')
SELECT T2。* FROM T2 WHERE CUST_ID IN(从T1选择CUST_ID T1.EMAIL LIKE'%sadpanda%')
I suggest first one . it will run faster then second one .
我建议先做一个。它将比第二个运行得更快。